当我们 Jackson 数据绑定时如何获取引用的 Pojo 名称 Json 对象

How to get Pojo name referenced Json object when we Jackson data-binding

我正在使用 Jackson 生成休息服务。我能够得到 JSON 这样的回复

[{"userName":"scott","userId":7},{"userName":"toe","userId":101}]

但我期待 Pojo 名称指向如下响应的响应

{"UserDetails":[{"userName":"scott","userId":7},{"userName":"toe","userId":101}]}

这是我的实现 class

@Service("userServices")
public class UserServiceImpl implements UserServices{

private UserServices userServices;

public UserServices getUserServices() {
    return userServices;
}
public void setUserServices(UserServices userServices) {
    this.userServices = userServices;
}

@Override
public List<UserDetails> getUser(UserDetails userDetails) {


    ObjectMapper mapper = new ObjectMapper();

    List<UserDetails> user = new ArrayList<UserDetails>();
    List<UserDetails> list = new ArrayList<UserDetails>();

    UserDetails userDetails2 = new UserDetails();
    userDetails2.setUserName("scott");
    userDetails2.setUserId(007);

    UserDetails userDetails3 = new UserDetails();
    userDetails3.setUserName("toe");
    userDetails3.setUserId(101);

    user.add(userDetails2);
    user.add(userDetails3);

    try{
    String jsonString = mapper.writeValueAsString(user);
    UserDetails[] userDetails4 = mapper.readValue(jsonString, UserDetails[].class);
    list = Arrays.asList(userDetails4);
    System.out.println(userDetails4);
    }catch (Exception e) {
        System.out.println(e);
    }
    return list;
}
}

这是我的 pojo

public class UserDetails implements Serializable{

private String userName;
private int userId;

public UserDetails(){

}

 //getters and setters...
}

** 注意:** 我不想在域对象端使用任何注释。

您 return 一个 UserDetails 列表,它转换为您的响应对象是一个 JSON 数组。为了获得您想要的结果,您需要创建一个 Container class (UserDetailsContainer),其中包含 属性 List 类型的 userDetails 和 return 作为响应的实例。

就return

用户详细信息响应:

public class UserDetailsResponse {

    private List<UserDetails> userDetails;
    // getter and setter

}

而不是 UserServiceImpl 中的 UserDetails 列表(然后可能在控制器中)。

您可以使用 objectMapper.writeValueAsString(aCustomMap) 即时创建自定义 json 视图。

示例:

UserDetails userDetails2 = new UserDetails();
userDetails2.setUserName("scott");
userDetails2.setUserId(007);

UserDetails userDetails3 = new UserDetails();
userDetails3.setUserName("toe");
userDetails3.setUserId(101);

Map<String, List<UserDetails>> m = new HashMap<>();
m.put("UserDetails", Arrays.asList(userDetails2, userDetails3));

System.out.print(
    //This is what you need
    objectMapper.writeValueAsString(m)
);
//{"UserDetails":[{"userName":"scott","userId":7},{"userName":"toe","userId":101}]}