在完成 left join 之后，我得到了重复的条目。需要知道如何删除重复条目

Question

LOAD EmployeeID,      
    SickLeaveHours,      
    (8760-SickLeaveHours-VacationHours)as QualityTimeHours,      
    (8760-SickLeaveHours-VacationHours)/24 as QualityDays,       
    ((8760-SickLeaveHours-VacationHours)/24)/30 as QualityMonths,       
    VacationHours;       

SQL SELECT EmployeeID,      
    SickLeaveHours,      
    VacationHours       
FROM Database;      

Join       
LOAD * INLINE [       
    F1, F2        
    ShiftID, Shift      
    1, DAY      
    2, EVENING     
    3, NIGHT      
];      

left join(fact)                 
b:     
LOAD 
    AddressID,
    EmployeeID;      
SQL SELECT 
    AddressID,
    EmployeeID      
FROM Database;      

left join(fact)     
c:     
LOAD 
   DepartmentID,
   EmployeeID;      
SQL SELECT 
   DepartmentID,
   EmployeeID     
FROM Database;           

left join(fact)        
LOAD ShiftID;       
SQL SELECT ShiftID       
FROM  Database;       

left Join (fact)       
d:       
LOAD EmployeeID,      
     Rate;       
SQL SELECT 
    EmployeeID,       
    Rate       
FROM Database ;        

empDetails:          
LOAD BirthDate,         
    EmployeeID,              
    Gender,             
    Title;       
SQL SELECT BirthDate,       
    EmployeeID,        
    Gender,        
    Title         
FROM  Database ;

Department:               
LOAD DepartmentID,         
    GroupName,            
    Name;      
SQL SELECT 
    DepartmentID,              
    GroupName,         
    Name              
FROM  Database;               

Address:           
LOAD AddressID,           
    ModifiedDate,        
    rowguid;           
SQL SELECT 
    AddressID,          
    ModifiedDate,        
    rowguid            
FROM  Database;            

shift:         
LOAD EndTime,       
    Name as name,       
    ShiftID,        
    StartTime;      
SQL SELECT 
    EndTime,         
    Name,         
    ShiftID,         
    StartTime         
FROM  Database;

预计 table，没有重复条目

Answer 1

你得到了重复项，因为几乎所有 table 都加入了 fact table，其中一些 table 没有公共键，这会导致交叉加入。例如：

left join(fact)        
LOAD ShiftID;       
SQL SELECT ShiftID       
FROM  Database;

上面的脚本只加载一个字段ShiftID，在fact table中不存在，连接基本上会执行交叉连接（all-to-all）

Qlik 在公共字段名称上加入 tables。如果您需要连接两个 table，那么这些 table 应该至少有一个公共字段。在您的示例中：fact 和 EmpAddress tables 将在 EmployeeID 字段上 joined/linked。

另一点：不要尝试总是将 table 合为一体。有时只 link 他们更好。否则您可以获得 wrong/duplicated 个答案。

例如：fact table 每个 EmployeeID 可以有多行，如果你加入（不是 link） EmpDetails table到 fact 然后计算 Gender 字段你将得到 wrong/duplicated 答案。在 one to many 的情况下，只有 link tables（两个 tables 应该有共同的领域，但他们没有加入。Qlik 会自动 link 他们)

下面的脚本是您的版本，没有 "hard" 连接到 fact（认为您不需要这些连接）

而且 - shifts 数据不会被 link 编辑成任何东西，因为它与员工 tables

没有任何公共字段

fact:
LOAD 
    EmployeeID,      
    SickLeaveHours,      
    (8760-SickLeaveHours-VacationHours)as QualityTimeHours,      
    (8760-SickLeaveHours-VacationHours)/24 as QualityDays,       
    ((8760-SickLeaveHours-VacationHours)/24)/30 as QualityMonths,       
    VacationHours;       
SQL SELECT EmployeeID,      
    SickLeaveHours,      
    VacationHours       
FROM Database;      

EmpAddress:     
LOAD 
    EmployeeID,
    AddressID;      
SQL SELECT 
    AddressID,
    EmployeeID      
FROM Database; 

EmpDepartment:     
LOAD 
   EmployeeID,
   DepartmentID;      
SQL SELECT 
   DepartmentID,
   EmployeeID     
FROM Database;           

EmpRate:       
LOAD EmployeeID,      
     Rate;       
SQL SELECT 
    EmployeeID,       
    Rate       
FROM Database;        

EmpDetails:          
LOAD
    EmployeeID,
    BirthDate,              
    Gender,             
    Title;       
SQL SELECT BirthDate,       
    EmployeeID,        
    Gender,        
    Title         
FROM  Database ;

Department:               
LOAD 
    DepartmentID,         
    GroupName,            
    Name             as DeprtmentName;      
SQL SELECT 
    DepartmentID,              
    GroupName,         
    Name              
FROM  Database;               

Address:           
LOAD AddressID,    
    ModifiedDate     as Address_ModifiedDate,        
    rowguid;           
SQL SELECT 
    AddressID,          
    ModifiedDate,        
    rowguid            
FROM  Database;            


// This part of the script will be isolated from the rest
// because there is no key to join on
shift:         
LOAD
    Name as ShiftName,       
    ShiftID,
    EndTime,
    StartTime;      
SQL SELECT 
    EndTime,         
    Name,         
    ShiftID,         
    StartTime         
FROM  Database;  

Join       
LOAD * INLINE [       
    ShiftID, Shift      
    1, DAY      
    2, EVENING     
    3, NIGHT      
];    

// Is this table needed at all?
LOAD ShiftID;       
SQL SELECT ShiftID       
FROM  Database;

在完成 left join 之后，我得到了重复的条目。需要知道如何删除重复条目

after doing left join i am getting duplicate entries. Need to know how to remove duplicate entries

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