SQL Qliksense 中的逻辑

Question

我想将客户端 IP table 和 PEP table 合并为两个字段。

|=========================|
|  Client ID |    PEP     |
|=========================|
|      1     |    Yes     |
|      1     |     No     |
|      2     |    Yes     |
|            |            |
==========================

在上面的 qliksense SQL table 中，每当客户端 ID 重复时，我应该能够 select 'Yes' 值并丢弃 'No'

经过逻辑，我的回答应该只有1是2否

这可以实现吗？

Answer 1

如果你想要的是仅在所有值都为 no 时显示 No，否则在 SQL 中显示 Yes 我会这样做

 SELECT ID
   CASE WHEN SUM(CASE WHEN PEP = 'Yes' THEN 1 ELSE 0 END) > 0 THEN 'Yes'
        ELSE 'No END AS PEP
 FROM Some_table_you_did_not_name
 GROUP BY ID

Answer 2

希望这对你有用：

select clientId, max(PEP)
from ip
group by clientId

Answer 3

不确定您是否正在查看仅限 Qlik 的解决方案，但下面的脚本是如何在 Qlik 脚本中实现的示例

作为这些脚本的结果，将有 2 个表（由 Client ID 字段链接）：

RawData - 每个客户多行
MaxData - 每个客户一行多一个字段表示客户端是否重复

选项 1：统计客户

RawData:
Load * Inline [
 Client ID, PEP
 1        , Yes
 2        , Yes
 1        , No 
];

MaxData:
Load
  [Client ID],
  if(ClientCount > 1, 'Yes', 'No') as Repeat
;
Load
  [Client ID],
  count([Client ID]) as ClientCount
Resident 
  RawData
Group By
  [Client ID]
;

选项 2：使用 peek 函数

RawData:
Load * Inline [
 Client ID, PEP
 1        , Yes
 2        , Yes
 1        , No 
];

// Load the same data but order it by the Client ID column
// create new field (RepeatsTemp) which compares the current Client ID value 
// with the previous one. If they are equal assign 1 else 0
TempData:
Load
  [Client ID],
  PEP,
  if([Client ID] = Peek([Client ID]), 1, 0) as RepeatsTemp
Resident
  RawData
Order By
  [Client ID]
;

// Load the TempData table and get the max of RepeatsTemp for 
// each Client ID (group by by Client ID)
// in the preceeding load "replace" 1 and 0 from the repeat field
// with 'yes' and 'no'
MaxData:
Load
  [Client ID],
  if(MaxRepeats = 1, 'Yes', 'No') as Repeats
;
Load
  [Client ID],
  max(RepeatsTemp) as MaxRepeats
Resident
  TempData
Group by
  [Client ID]
;

// we dont need this table anymore
Drop Table TempData;

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