从 NSIS 中的时间戳获取日期

Question

我是 NSIS 的新手，我想从给定的时间戳中获取日期、小时、分钟等。

有什么办法吗？

提前感谢您的任何回答...

Answer 1

!include LogicLib.nsh
Section
StrCpy [=10=] 1568807339 ; UNIX time
System::Int64Op [=10=] * 10000000
System::Int64Op 116444736000000000 + ; support.microsoft.com/en-us/help/167296/how-to-convert-a-unix-time-t-to-a-win32-filetime-or-systemtime
System::Call 'KERNEL32::FileTimeToLocalFileTime(*ls,*l.s)' ; This line is optional, comment it out if you want to keep it UTC
System::Call 'KERNEL32::FileTimeToSystemTime(*ls,@r0)i.r1' ; NSIS v3+
${If}  <> 0
    System::Call '*[=10=](&i2.r1,&i2.r2,&i2,&i2.r3,&i2.r4,&i2.r5,&i2.r6)'
    IntFmt  "%.2d" 
    IntFmt  "%.2d" 
    IntFmt  "%.2d" 
    IntFmt  "%.2d" 
    IntFmt  "%.2d" 
    DetailPrint "// ::"

    System::Call 'KERNEL32::GetDateFormat(i0x0400,i0,pr0,p0,t.r1,i666)'
    System::Call 'KERNEL32::GetTimeFormat(i0x0400,i0,pr0,p0,t.r2,i666)'
    DetailPrint " "
${EndIf}
SectionEnd

从 NSIS 中的时间戳获取日期

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