将整数序列与元组和可变参数模板一起使用

Using integer sequences with tuples and variadic templates

假设我有一个元组:

std::tuple<int, char, unsigned int> t{1, 'a', 4}

如何使用 std::index_sequence 和朋友迭代上述元组的类型,以便我可以使用(或在需要时重写)下面的函数 to_token

template<typename P1, typename... Param>
std::vector<std::string> to_token(const P1& p1, const Param&... param) {
    const auto to_token_impl = [](const auto& t) {
        using ParamType = std::decay_t<decltype(t)>;
        std::stringstream ss;

        if constexpr (std::is_same_v<ParamType, char>)
            ss << "char";
        else if constexpr (std::is_integral_v<ParamType>) {
            ss << "integral";
        }
        return ss.str();
    };
    return {to_token_impl(p1), to_token_impl(param)...};
}

预期输出:{ "integral", "char", "integral" }

根据 here 找到的示例,我已经开始研究这种间接方法,但我无法确定下一步该做什么...

template<typename... Args>
void tokenize(const std::tuple<Args...>& t) {
    tokenize_impl(t, std::index_sequence_for<Args...>{});
}

template<typename Tuple, std::size_t... Is>
void tokenize_impl(const Tuple& t, std::index_sequence<Is...>) {
    // ?
}
template<typename... Args>
decltype(auto) tokenize(const std::tuple<Args...>& t) {
    return std::apply(
        [](auto const &... o) -> decltype(auto) { return to_token(o...); },
        t
    );
}

lambda需要推迟to_token的参数推导,直到它真正发生在std::apply内部,否则to_token没有明确的类型,无法传递作为参数。

std::string typeToString(int) {
    return "integral";
}

std::string typeToString(char) {
    return "char";
}
// overload this method to support other types

template<typename Tuple, std::size_t... Is>
auto tokenize_impl(const Tuple& t, std::index_sequence<Is...>) {
    return std::vector<std::string>( {typeToString(std::get<Is>(t))...} );
}

template<typename... Args>
auto tokenize(const std::tuple<Args...>& t) {
    return tokenize_impl(t, std::index_sequence_for<Args...>{});
}


int main() {
    auto t = std::make_tuple(1,'a',4);
    auto res = tokenize(t);
    for (auto elem : res)
        std::cout << elem << std::endl;
}

作为输出:

integral
char
integral

Live demo