空手道 - 如何将正文作为表单数据发送

Question

这些是我在表单数据中的字段

uploaded_by = x@y.com
status = true
file = Excel File to be uploaded

这是我试过的代码

    Given url baseUrl + uploadTemplate
    And multipart field uploaded_by = <user>
    And multipart field status = <status>
    And multipart field file = read('Template.xlsx')
    When method post
    Then status 200
    And match $.result == <result>

Examples: 
| user      | status | result  |
| 'x@y.com' | true   | INITIAL |

Excel 文件与功能文件所在的位置相同，我收到 500 错误，但在 POSTMAN

中运行良好

Answer 1

使用form field代替multipart field：https://github.com/intuit/karate#form-field

Answer 2

它适用于以下代码

    Given url baseUrl + uploadTemplate
    And multipart field uploaded_by = <user>
    And multipart field status = <status>
    And multipart field file = { read: 'Template.xlsx', filename: 'Template.xlsx', contentType: 'multipart/form-data' }
    When method post
    Then status 200
    And match $.result == <result>

空手道 - 如何将正文作为表单数据发送

Karate - how to send body as form data

form-data

karate