django 2.2.5 import url 从一个应用程序到另一个应用程序

Question

我想在搜索应用 url (search/urls.py) 中使用来自产品应用 (products/urls.py) 的 url 来搜索 items/products 使用搜索栏。我在 django docs but it's importing a view to url in the same app, and I've also attempted this example 上尝试过这个例子，但它看起来是旧版本 django 的解决方案，但我在 time time 2.2.5.

使用最新版本的 django

我在终端中收到的错误消息来自 search/urls.py:

path('', views.ProductListView.as_view(), name='list'), AttributeError: module 'search.views' has no attribute 'ProductListView'

我知道 search.views 没有属性 "ProductListView" 但是 products.views 有，这就是为什么我要在 [=30= 中导入 products.views ].py.

products/urls.py

from django.urls import path, re_path
from .import views

app_name = "products"

urlpatterns = [
    path('', views.ProductListView.as_view(), name='list'),
    re_path(r'^products/(?P<slug>[\w-]+)/$', views.ProductDetailSlugView.as_view(), name='detail'),

]

search/urls.py

from django.urls import path
from .import views
from products.views import ProductListView

urlpatterns = [
    path('', views.ProductListView.as_view(), name='list'),

]

ecommerce/urls.py（主应用）

from django.conf import settings
from django.conf.urls.static import static
from django.contrib import admin
from django.urls import path, include, re_path

# from products.views import ProductDetailView

from .views import home, about, contact

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', home, name='home'),
    path('about/', about, name='about'),
    path('contact/', contact, name='contact'),
    path('account/', include('allauth.urls'), name='login'),
    path('register/', include('allauth.urls'), name='register'),
    path('products/', include('products.urls', namespace='products')),
    path('search/', include('search.urls', namespace='search')),

    # path('', include('products.urls'), name='products-featured'),
    # path('', include('products.urls'), name='featured-details'),
    # path('', include('products.urls'), name='featured-slug-details'),
              ] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT) + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

Answer 1

您有：

from products.views import ProductListView

因此您应该使用 ProductListView，而不是 views.ProductListView

urlpatterns = [
    path('', ProductListView.as_view(), name='list'),
    ...
]

请注意，您可以删除 from .import views 导入，除非您在 search/urls.py

中的其他地方使用 views

另一种方法是使用 import as，这样您就可以从同一模块中的不同应用导入多个 views.py：

from products import views as product_views

urlpatterns = [
    path('', product_views.ProductListView.as_view(), name='list'),
]

django 2.2.5 import url 从一个应用程序到另一个应用程序

django 2.2.5 import url from one app to another app

python

django

django-urls