ValueError: cannot reshape array of size 23760 into shape (240,1,28,28)

Question

# Reshape and normalize training data
trainX = train[:, 1:].reshape(train.shape[0],1,28, 28).astype( 'float32' )
x_train = trainX / 255.0

y_train = train[:,98]

# Reshape and normalize test data
testX = test[:,1:].reshape(test.shape[0],1, 28, 28).astype( 'float32' )
x_test = testX / 255.0

y_test = test[:,98]

我尝试将我的 csv train_data 和 test_data 重塑为 3-D 矩阵，但出现错误：

ValueError Traceback (most recent call last) 
<ipython-input-57-268af51a6b14> in <module>()
----> 1 trainX = train[:, 1:].reshape(train.shape[0],1,28, 28).astype( 'float32' )
      2 x_train = trainX / 255.0
      3
      4 y_train = train[:,98]
      5
ValueError: cannot reshape array of size 23760 into shape (240,1,28,28)

Error Report Screenshoot

Answer 1

正如评论中已经提到的，23760 != 240*1*28*28，因此无法重塑为该特定数组。事实上，28*28 连 23760 都不能整除，所以即使 train.shape[0] 换成其他东西，这也是行不通的。

假设 train.shape[0] 和 1 是您想要用于前两个维度的内容，最终维度的乘积需要为 23760/240 = 99。因为这不是一个平方数，这两个数字将不得不不同。 99 的质因数分解是 99 = 3*3*11，所以唯一可能的选项是

(240, 1, 1, 99), (240, 1, 3, 33), (240, 1, 9, 11),

及其排列。

ValueError: cannot reshape array of size 23760 into shape (240,1,28,28)

ValueError: cannot reshape array of size 23760 into shape (240,1,28,28)

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