如何将对象数组的所有属性设置为 true？

Question

我有一些 JSON 数据，我正在尝试映射并将所有属性设置为 true。

我知道您可以为此使用 map 函数，但是 JSON 的设置方式是，数组中的每个对象都有一个键名。

所以当我运行映射函数时，它将所有键名设置为 false，而不是对象本身内部的属性。

这里是 JSON 数据：

{
    "Presentations": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 5
    },
    "Articles": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 1
    },
    "Blogs": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 61
    },
    "NewsBriefs": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 2
    },
    "SpecialInsights": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 50
    }
}

这里是我尝试的map函数，其中data指的是上面的JSON：

Object.entries(data).map(([key, value]) => {
     return value === true;
});

这又是 returns 一个包含值 false 的五个项目的数组：

[false,false,false,false,false]

我正在尝试做的是将任何错误的项目的值翻转为正确的。

Answer 1

你不需要映射任何东西

var arr = your_json;
for(a in arr){
    arr[a]['Instant'] = true;
    arr[a]['Daily'] = true;
    arr[a]['WeeklySummary'] = true;
}

如果您不知道属性

for(a in arr){
    for(e in arr[a]){
        !arr[a][e] ? arr[a][e] = true : null
    }
}

Answer 2

使用递归：

function flip(o) {
  for (k of Object.keys(o)) {
    if (typeof o[k] === "object") {
      flip(o[k])
    }
    if (o[k] === false) {
      o[k] = true;
    }
  }
}



const o = {
    "Presentations": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 5
    },
    "Articles": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 1
    },
    "Blogs": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 61
    },
    "NewsBriefs": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 2
    },
    "SpecialInsights": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 50
    }
}

flip(o);
console.log(o);

Answer 3

根据您的 ES 版本和所需的浏览器支持，这里有几种不同的方法。

var data = {
    "Presentations": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 5
    },
    "Articles": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 1
    },
    "Blogs": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 61
    },
    "NewsBriefs": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 2
    },
    "SpecialInsights": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 50
    }
};

/* ES5 */
var outterKeys = Object.keys(data);
for(var o = 0; o < outterKeys.length; o++){
  var outterObject = data[outterKeys[o]];
  var innerKeys = Object.keys(outterObject);
  for(var i = 0; i < innerKeys.length; i++){
    var innerObject = outterObject[innerKeys[i]];
    if (!innerObject){
      data[outterKeys[o]][innerKeys[i]] = true;
    }
  }
}

console.log('es5', data);

/* ES6 */
data = {
    "Presentations": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 5
    },
    "Articles": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 1
    },
    "Blogs": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 61
    },
    "NewsBriefs": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 2
    },
    "SpecialInsights": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 50
    }
};

Object.keys(data).forEach((o) => {
  Object.keys(data[o]).forEach((i) => {
    if (!data[o][i]){
      data[o][i] = true
    }
  })
});
console.log('es6', data);

Answer 4

您也可以简单地使用嵌套的 forEach 来做到这一点，就像这样 -

    const a = {
      "Presentations": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 5
    },
    "Articles": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 1
    },
    "Blogs": {
        "Instant": true,
        "Daily": false,
        "WeeklySummary": true,
        "ContentTypeId": 61
    },
    "NewsBriefs": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 2
    },
    "SpecialInsights": {
        "Instant": false,
        "Daily": false,
        "WeeklySummary": false,
        "ContentTypeId": 50
    }
}
    
    Object.keys(a).forEach(ele => {
     Object.keys(a[ele]).forEach(childEle => {a[ele][childEle] = true});
    })
    
    console.log(a);

如何将对象数组的所有属性设置为 true？

How can I set all the properties of an array of objects to true?

javascript

arrays

json

javascript-objects

underscore.js