在 Laravel 中合并 2 个数据变量
Combine 2 data variable in Laravel
如何在 Laravel 中组合 2 个可变数据。我正在尝试将 $income1 和 $income2 中的数据合并为 $income data show all data from $income1 and $income2
这是我的控制器
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use Illuminate\Support\Collection;
use App\Product;
use App\Blok;
class ProductController extends Controller
{
public function income()
{
$products = Product::all();
$income1 = \App\Pembelian::join('debitur','debitur.id','=','pembelian.debiturID')
->join('blok','blok.blok_id', '=', 'debitur.blokID')
->join('products','products.id', '=', 'blok.productID')
->get();
$income2 = \App\Pembayaran::join('angsuran','angsuran.id','=','pembayaran.angsurID')
->join('debitur','debitur.id','=','angsuran.debiturID')
->join('blok','blok.blok_id', '=', 'debitur.blokID')
->join('products','products.id', '=', 'blok.productID')
->get();
$income = collect($income1, $income2);
$income->all();
return view('income', compact('products', 'income'));
}
}
但它最终只显示 $income1 数据。
使用array_merge
$merge = array_merge($income1, $income2);
最简单的方法是使用
合并
$merged = $income1->merge($income2);
$income = $merged->all();
因此您将能够使用 $income 来引用这两个变量!
我解决了
使用最简单的方法union
$payment = Pembayaran::select("pembayaran.penyetor","pembayaran.jumlah_bayar","pembayaran.jenis","pembayaran.lsd","pembayaran.tanggal","pembayaran.keterangan","pembayaran.blok_id");
$incomes = Pembelian::select("pembelian.penyetor","pembelian.jumlah_bayar","pembelian.jenis","pembelian.lsd","pembelian.tanggal","pembelian.keterangan","pembelian.blok_id")
->union($payment)
->orderBy('tanggal', 'desc')
->get();
如何在 Laravel 中组合 2 个可变数据。我正在尝试将 $income1 和 $income2 中的数据合并为 $income data show all data from $income1 and $income2
这是我的控制器
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use Illuminate\Support\Collection;
use App\Product;
use App\Blok;
class ProductController extends Controller
{
public function income()
{
$products = Product::all();
$income1 = \App\Pembelian::join('debitur','debitur.id','=','pembelian.debiturID')
->join('blok','blok.blok_id', '=', 'debitur.blokID')
->join('products','products.id', '=', 'blok.productID')
->get();
$income2 = \App\Pembayaran::join('angsuran','angsuran.id','=','pembayaran.angsurID')
->join('debitur','debitur.id','=','angsuran.debiturID')
->join('blok','blok.blok_id', '=', 'debitur.blokID')
->join('products','products.id', '=', 'blok.productID')
->get();
$income = collect($income1, $income2);
$income->all();
return view('income', compact('products', 'income'));
}
}
但它最终只显示 $income1 数据。
使用array_merge
$merge = array_merge($income1, $income2);
最简单的方法是使用
合并
$merged = $income1->merge($income2);
$income = $merged->all();
因此您将能够使用 $income 来引用这两个变量!
我解决了
使用最简单的方法union
$payment = Pembayaran::select("pembayaran.penyetor","pembayaran.jumlah_bayar","pembayaran.jenis","pembayaran.lsd","pembayaran.tanggal","pembayaran.keterangan","pembayaran.blok_id");
$incomes = Pembelian::select("pembelian.penyetor","pembelian.jumlah_bayar","pembelian.jenis","pembelian.lsd","pembelian.tanggal","pembelian.keterangan","pembelian.blok_id")
->union($payment)
->orderBy('tanggal', 'desc')
->get();