检查手牌中是否有两对 Python

Question

我正在尝试检查随机手中是否有两对。我现在有它，它会打印一对，所以它会打印那张卡片出现的次数，所以如果有 2 个，它将是 2 x 2，所以第一个数字是出现，然后第二个数字是卡号然后打印一对。

我如何让它打印两对而不是所以检查一手 5 是否有让我们说例如 2 x 2 和 2 x 5 所以一对 2 和 5然后打印出 "two pairs".

我在 numbers = cards.count(card) 中添加了它下面的 if 语句然后 numbers == 2 所以如果有一对和一对它打印两对和得到它的概率。

def twopair():
    count = 0
    while True:
        cards = []
        for i in range(5):
            cards.append(random.choice([1,2,3,4,5,6,7,8,9,10,11,12,13]))
        stop = False
        for card in cards:
            number = cards.count(card) # Returns how many of this card is in your hand
            numbers = cards.count(card)
            print(f"{number} x {card}")
            if(number == 2 and numbers == 2):
                print("One Pair")
                stop = True
                break
        if stop:
            break
        else:
            count += 1
    print(f'Count is {count}')

Answer 1

查看 collections 模块中的 Counter。 https://docs.python.org/3/library/collections.html#collections.Counter

import random
from collections import Counter


def twopair():
    while True:
        cards = []
        for i in range(5):
            cards.append(random.choice([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]))

        counted_cards = Counter(cards)
        two_most_common, count = zip(*counted_cards.most_common(2))

        count_to_message = {
            (1, 1): "Nothing",
            (2, 1): "One Pair",
            (3, 1): "Three of a Kind",
            (4, 1): "Four of a Kind",
            (5, 1): "Whoops, who's cheating",
            (2, 2): "Two Pairs",
            (3, 2): "Full House",
        }

        msg = count_to_message[count]
        print(msg)
        if msg == "Two Pairs":
            break


twopair()

检查手牌中是否有两对 Python

Checking if theres two pairs in card hand Python

python

random

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