Python 中的 RSA 解密我如何获得字节数组？

Question

我正在尝试通过 Python 使用 RSA。

我使用 Python 中生成的 public 密钥从 .net 进行加密。加密一切顺利。当我解密我的加密句子时，我无法恢复到正确的值。

如何将我的值转换回字节数组？我确定我很接近......但什么也没找到

我用我的 public 密钥加密了这个字节数组，但是当我解密时我无法取回它

 [0]    3   byte
 [1]    180 byte
 [2]    214 byte
 [3]    196 byte
 [4]    37  byte
 [5]    120 byte
 [6]    213 byte
 [7]    71  byte
 [8]    143 byte
 [9]    64  byte
 [10]   168 byte
 [11]   245 byte
 [12]   172 byte
 [13]   178 byte
 [14]   120 byte
 [15]   114 byte

我使用的public键是：

我的私钥是：

我收到的输出是：

b"\x02-qf\xcc\xf8\x1c\xdc_bV\xa7\x84o\xc7K2k\xe6\xf0\xd4\x8e\x96\xef9\xbb\xe7%j\xa4h\xd5\xcd\xc1c\x0b\t\x98\x9d\xde\xd9\xe7\xe0druq\x90\xfc\xa5O\xd5\xd4\xb6\xec>\xbb($\x02u^\xb8\xe0\xd2W\x8bzL\x1f\xc0\x05\x1c\xf1\xea7\x99\x06\xd0\xa7ov\xa8A\xc3\x0b\x03\xf9\x1a\xac\x92Gn\xa7\xf0\x93v\xd0\xda\x89)G8\xc2e\xd4\xf5\te\x97\xcf a\x9e\xb5\xeei\xc4\xfci\xcd=/\xd3\xa5\x1fE\x0e\xcf\xaeD\x9fHA\x930\xa9EV\xee\x83\x17f\xe9\xc1\xb4\xc7s\xef%F\xb6!\xb4j\x14\xd4\xf1K\xa3r\x90\xbfI\xfd;\xca>zUcR\x16m\x82\x81iz\xb4C\xed\x1e\xdc\xa9\xfc\x0f\x87\xd7-\xde\x9f(l\x042^e\x84\x15\xb2k\x08\x82@\xd3m\x7f\x95\xabvM\xe6\x88\xb2;_\x0f'\xae\xdbvp\x83\xd6\xba\xc0F\x16\x87\xf1\xf0Y\x1fF~L\x18\x1d\x00\x03\xb4\xd6\xc4%x\xd5G\x8f@\xa8\xf5\xac\xb2xr"

有我的代码

我得到一个CryptoHelper.py

from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
from Crypto.Util import number

import base64

class CryptoHelper:
    PrivateKeySize = 2048 
    def CreateRSA_CSP(self):       
        csp = RSA.generate(self.PrivateKeySize)           
        return csp
    def GetRSA_PublicKey(self, csp):
        return str(csp.publickey().exportKey(format='PEM'),"utf-8")
    def RSAEncrypt(self,publicKEY,byteArray):
        csp =  RSA.importKey(publicKEY);
        encrypted = csp.encrypt(byteArray)
        return base64.standard_b64encode(encrypted)
    def RSADecrypt(self,csp, byteArray):
        return csp.decrypt(byteArray)

那是我的HandShakeHelper.py

import json
import requests
import base64
import uuid
from Helpers import CryptoHelper

class HandShakeHelper:
    CSP = None
    CryptoHelper = None

    def __init__(self,serial,endPoint):
        self.Serial = serial
        self.EndPoint = endPoint    
    def GenerateHandShakeKey(self):        
        self.CryptoHelper = CryptoHelper.CryptoHelper()
        self.CSP = self.CryptoHelper.CreateRSA_CSP()
        self.InitializeHandShake()
    def InitializeHandShake(self):
        print(str(self.CSP.exportKey(format='PEM'),"utf-8"))
        print(self.CryptoHelper.GetRSA_PublicKey(self.CSP))
        headers = { "Content-Type" : "application/json" }
        args = '{ args : { "Publickey" : "' + self.CryptoHelper.GetRSA_PublicKey(self.CSP) + '", "Serial" : "' + self.Serial + '" }}'
        answer = requests.post(url = self.EndPoint +"/InitializeHandShake", headers=headers, data = args)
        se_answer_raw = json.loads(answer.text)
        se_answer = se_answer_raw["d"]
        if(se_answer["Status"]==200):           
            cryptedBase64HandShakeId = base64.standard_b64decode(se_answer["CryptedHandShakeID"])  

            decryptedBytes = self.CSP.decrypt(cryptedBase64HandShakeId)
            print(decryptedBytes)

握手助手调用网络服务。将 public 密钥发送到服务器，服务器 return 使用 public 密钥加密了一个我尝试解密的 CryptedToken。

那是我的Test.py

from Helpers import HandShakeHelper, CryptoHelper 



handShake = HandShakeHelper.HandShakeHelper("8047771c-b1b0-408d-91ad-eacbc03ae6ca","http://www.localhost.com/webservice.asmx")
handShake.GenerateHandShakeKey()

.net 部分是这个

CryptoHelper.EncryptRSAContent(clientPublicKey, MyGuid.ToByteArray(), false)

public static byte[] EncryptRSAContent(string publicKey, byte[] content, bool fOAEP)
    {
      byte[] cryptedData = null;
      using (RSACryptoServiceProvider RSA = new RSACryptoServiceProvider())
      {
        if (publicKey.StartsWith("<RSAKeyValue>"))
        {
          RSA.FromXmlString(publicKey);
        }
        else
        {

          PEMCrypto.ImportPublicKey(publicKey, RSA);
        }

        cryptedData = RSA.Encrypt(content, fOAEP);
      }
      return cryptedData;
    }

Answer 1

感谢@t.m.adaam 它工作正常

我用那个版本更正了我的CryptoHelper.py

from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_v1_5
from Crypto.Util import number
from Crypto import Random

import base64

class CryptoHelper:
    PrivateKeySize = 2048     
    def CreateRSA_CSP(self):       
        csp = RSA.generate(self.PrivateKeySize)
        return csp
    def GetRSA_PublicKey(self, csp):
        return str(csp.publickey().exportKey(format='PEM'),"utf-8")
    def RSAEncrypt(self,publicKEY,byteArray):
        csp =  RSA.importKey(publicKEY);
        rsa_csp = PKCS1_v1_5.new(csp)
        return base64.standard_b64encode(rsa_csp.encrypt(byteArray))
    def RSADecrypt(self,csp, byteArray):
        sentinel = Random.new().read(256)
        rsa_csp = PKCS1_v1_5.new(csp)
        return rsa_csp.decrypt(byteArray,sentinel)

Python 中的 RSA 解密我如何获得字节数组？

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