Python 搜索两个词正则表达式

Question

我正在尝试查找一个句子是否包含短语 "go * to"，例如 "go over to"、"go up to" 等。我正在使用 Textblob，我知道我可以只需在下面使用：

search_go_to = set(["go", "to"])
go_to_blob = TextBlob(var)
matches = [str(s) for s in go_to_blob.sentences if search_go_to & set(s.words)]
print(matches)

但这也会 return 像 "go over there and bring this to him" 这样的句子，这是我不想要的。任何人都知道我如何做 text.find("go * to")?

Answer 1

这个有用吗？

import re
search_go_to = re.compile("^go.*to$")
go_to_blob = TextBlob(var)
matches = [str(s) for s in go_to_blob.sentences if search_go_to.match(str(s))]
print(matches)

正则表达式的解释：

^    beginning of line/string
go   literal matching of "go"
.*   zero or more characters of any kind
to   literal matching of "to"
$    end of line/string

如果不希望"going to"匹配，在to之前和go之后插入一个\b（单词边界）。

Answer 2

尝试使用：

for match in re.finditer(r"go\s+\w+\s+to", text, re.IGNORECASE):

Answer 3

使用generator expressions

>>> search_go_to = set(["go", "to"])
>>> m = ' .*? '.join(x for x in search_go_to)
>>> words = set(["go over to", "go up to", "foo bar"])
>>> matches = [s for s in words if re.search(m, s)]
>>> print(matches)
['go over to', 'go up to']

Answer 4

试试这个

text = "something go over to something"

if re.search("go\s+?\S+?\s+?to",text):
    print "found"
else:
    print "not found"

正则表达式：-

\s is for any space
\S is for any non space including special characters
+? is for no greedy approach (not required in OP's question)

所以 re.search("go\s+?\S+?\s+?to",text) 会匹配 "something go W#$%^^$ to something" 当然这也是 "something go over to something"

Python 搜索两个词正则表达式

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