如何在 Java 中获取真实路径 InputStream 文件 Rest API

Question

我有一个 Java Rest API Post 方法发送图像 (InputStream) 作为参数，我必须将它保存在 Oracle 的 blob 列中。

我需要获取此 InputStream 的完整路径（真实路径）以将此图像保存在数据库中。我的代码如下。

@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
                @FormDataParam("file") InputStream uploadedInputStream,
                @FormDataParam("file") FormDataContentDisposition fileDetail) {
String UPLOAD_FOLDER = "c:/uploadedFiles/"; // my rest api does not have this file, how to get at runtime?    
String uploadedFileLocation = UPLOAD_FOLDER + fileDetail.getFileName(); // this line is ok

我想做这样的事情：

String UPLOAD_FOLDER = uploadedInputStream.getRealPathName();

或

String UPLOAD_FOLDER = fileDetail.getRealPathName();

Answer 1

我通过将输入流转换为字节数组解决了这个问题。我将 byte[] 转发给数据库持久化方法。我的代码如下：

public byte[] toByteArray(InputStream is) throws IOException{
    ByteArrayOutputStream baus = new ByteArrayOutputStream();
    byte[] buffer = new byte[1024];
    int len;
    while((len= is.read(buffer)) != -1){
        baus.write(buffer, 0, len);
    }
    return baus.toByteArray();
}

@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
                @FormDataParam("file") InputStream uploadedInputStream,
                @FormDataParam("file") FormDataContentDisposition fileDetail) {
    ...
    byte[] b = toByteArray(uploadedInputStream);
    business.saveUploadedFileInDatabase(b);
    ...
}

public boolean uploadFile(byte[] b) throws SQLException, IOException{
    ...
    PreparedStatement ps = conn.prepareStatement("INSERT INTO TABLE_IMAGE_TEST (CODE, IMAGE) VALUES (?, ?)");
    pstmt.setLong(1, 1L);
    pstmt.setBytes(2, b);
    pstmt.execute();
    ...
}

如何在 Java 中获取真实路径 InputStream 文件 Rest API

How to get real path InputStream file in Java Rest API

java

rest

inputstream

fileinputstream

bufferedinputstream