如何使用 apache camel 而不是 xml 记录列表将平面文件中的单个记录转换为一个 xml

Question

CamelConfig.java

@Component
public class CamelConfig extends RouteBuilder {
    @Override
    public void configure() throws Exception {
        try {
            CamelContext context = new DefaultCamelContext();
            ConverterRoute route = new ConverterRoute();
            route.addRoutesToCamelContext(context);
            context.start();
            Thread.sleep(5000);
            context.stop();

        } catch (Exception exe) {
            exe.printStackTrace();
        }
    }
}

ConverterRoute.java

public class ConverterRoute implements RoutesBuilder {

    private static final String SOURCE_INPUT_PATH = "file://inbox?fileName=Source.txt";

    private static final String SOURCE_OUTPUT_PATH = "file://outbox?fileName=file.xml";

    public void addRoutesToCamelContext(CamelContext context) throws Exception {

        context.addRoutes(new RouteBuilder() {
            public void configure() {
                try {
                    DataFormat bindyFixed = new BindyCsvDataFormat(Test.class);

                    from(SOURCE_INPUT_PATH).
                            unmarshal(bindyFixed).
                            marshal().
                            xstream().
                            to(SOURCE_OUTPUT_PATH).log("Finished Transformation").end();
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        });
    }

Source.txt

55158|11901|2346
55158|11101|3454

Test.java

@CsvRecord(separator = "\|",skipField = true,name = "Test")
public class Test {

    @DataField(pos = 1,name = "ALT_NUM")
    private BigDecimal ALT_NUM;

    @DataField(pos = 2,name = "PRTNUM")
    private BigDecimal PRTNUM;

    @DataField(pos = 3,name = "UOMCOD")
    private Integer UOMCOD;

}

输出

* File.xml*

<?xml version='1.0' encoding='UTF-8'?>
<list>
    <com.john.Test>
            <ALT_NUM>55158</ALT_NUM>
            <PRTNUM>11901</PRTNUM>
            <UOMCOD>2346</UOMCOD>
    </com.john.Test>
    <com.john.Test>
            <TRNNAM>55158</TRNNAM>
            <PRTNUM>11901</PRTNUM>
            <UOMCOD>3454</UOMCOD>
    </com.john.Test>
</list>

预期输出

fileOne.xml

<?xml version='1.0' encoding='UTF-8'?>    
    <Test>
            <ALT_NUM>55158</ALT_NUM>
            <PRTNUM>11901</PRTNUM>
            <UOMCOD>2346</UOMCOD>
    </Test>

fileTwo.xml

<?xml version='1.0' encoding='UTF-8'?>    
    <Test>
            <ALT_NUM>55158</ALT_NUM>
            <PRTNUM>11901</PRTNUM>
            <UOMCOD>3454</UOMCOD>
    </Test>

我能够生成 xml 文件，其中所有字段都在单个 file.I 中，想要单个 xml 文件中的单个记录。任何人都可以帮助 me.Also 输出文件根元素中的标签名称它正在生成 class.

的包名称

Answer 1

您或许可以使用 split() 分别处理 csv 记录中的每一行。

from(SOURCE_INPUT_PATH).
 .split().tokenize(System.lineSeparator())
   unmarshal(bindyFixed).
   marshal().
   xstream().
   to(SOURCE_OUTPUT_PATH).log("Finished Transformation").end();

如何使用 apache camel 而不是 xml 记录列表将平面文件中的单个记录转换为一个 xml

How to transform individual record in flat file to one xml using apache camel instead of list of xml records

java

apache-camel

bindy

spring-camel