JSON对象属性转化为JSON对象名称

Question

我有一个 JSON 文件，其中包含很多这样的对象（例如 Pikemen 单位的属性 >Heroes 3 btw<）：

[ {
        "ID": 0,
        "AI": 80,
        "": null,
        "Level": 0,
        "Growth": 14,
        "Low": 20,
        "High": 50,
        "Town": 0,
        "Name": "Pikeman",
    }, etc.. ]

如何让 "Name" 属性成为 JSON 文件中每个对象的名称？在 JS 代码中或通过格式化文件。我的意思是：

[ "Pikeman": {
       "ID": 0,
       "AI": 80,
       etc..
} ]

Answer 1

这样使用：

let obj = [{
        "ID": 0,
        "AI": 80,
        "": null,
        "Level": 0,
        "Growth": 14,
        "Low": 20,
        "High": 50,
        "Town": 0,
        "Name": "Pikeman",
    },{
        "ID": 0,
        "AI": 82220,
        "": null,
        "Level": 230,
        "Growth": 14,
        "Low": 20213,
        "High": 12312050,
        "Town": 10,
        "Name": "Pikeman2",
    }]

obj.forEach((item, index) => {
  obj[item.Name] = item;
  delete obj[index];
})

console.log(obj)

Answer 2

你好@Adrian 你可以遍历你的数组并获取名称并将 int 指定为键检查这个：

let obj = [ {
        "ID": 0,
        "AI": 80,
        "": null,
        "Level": 0,
        "Growth": 14,
        "Low": 20,
        "High": 50,
        "Town": 0,
        "Name": "Pikeman",
    }, 
    {
        "ID": 0,
        "AI": 80,
        "": null,
        "Level": 0,
        "Growth": 14,
        "Low": 20,
        "High": 50,
        "Town": 0,
        "Name": "Pikeman1",
    }, 
    {
        "ID": 0,
        "AI": 80,
        "": null,
        "Level": 0,
        "Growth": 14,
        "Low": 20,
        "High": 50,
        "Town": 0,
        "Name": "Pikema2",
    }]

    let objConverted = {};

    obj.forEach( o => {
      objConverted[o.Name] = o; 
    } ) 

    console.log(objConverted);

如果您想使用代码，请选中此选项：https://repl.it/repls/HalfSatisfiedMainframe

JSON对象属性转化为JSON对象名称

JSON Object property into JSON Object name

javascript

json

object

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typescript