Select 每组前 15 条记录

Question

我想select10个商家账户，为每个商家账户选择前15条交易记录，页面大小为10*50？

我有这个查询，它为我提供了最高记录，我需要修复以选择 "top 15 records for each merchant account id" 而不仅仅是前 150 条记录。

欢迎任何指点、建议和代码修复！

SELECT * FROM (
             SELECT account_id,transaction_id,ROWNUM RNUM
             FROM transactions 
             WHERE status='P' AND ROWNUM < ( (p_page_number * p_page_size) + 1)
             GROUP BY account_id,transaction_id, ROWNUM
             ORDER BY account_id                 
             ) a
      WHERE rnum >= ( ( (p_page_number - 1) * p_page_size) + 1);

Answer 1

这会给你"top 15 records for each merchant account id"：

SELECT *
FROM (
  SELECT 
    account_id, 
    transaction_id, 
    ROW_NUMBER() OVER(
      PARTITION BY account_id -- Break into groups of merchants
      ORDER BY transaction_id -- Assign row number based on transaction, within merchants
    ) RowNum
  FROM transactions
  WHERE status='P'
) src
WHERE src.RowNum <= 15
ORDER BY account_id, transaction_id

我不太确定您的 p_page_number, p_page_size, and ROWNUM 参数是如何发挥作用的。

Answer 2

您可以使用 DENSE_RANK() window 函数为行分配组号，并使用 ROW_NUMBER() 为每个组分配一个序列号。然后，过滤很容易。

例如：

select *
from (
  select
    account_id, 
    transaction_id,
    dense_rank() over(order by account_id) as g,
    row_number() over(partition by account_id order by transaction_id) as rn
  from transactions
  where status = 'P'
) x
where g <= 10 -- the first 10 groups (accounts)
  and rn <= 15 -- the first 15 transactions within each group

Select 每组前 15 条记录

Select top 15 records from each group

sql

oracle

paging

filtering

greatest-n-per-group