我需要知道如何测试一个值是否不等于多个字符串 java
I need to know how to test if a value is not equal to multiple strings java
我该怎么做?
我想测试符号行 2 (1) 是否等于 "Closed" 或 "Open" 如果不是我想说请指定它是打开还是关闭它说如果我输入打开或关闭
|| 在哪里是行不通的...
package me.mcmatt.shops;
import org.bukkit.ChatColor;
import org.bukkit.Material;
import org.bukkit.Sound;
import org.bukkit.block.Block;
import org.bukkit.block.Sign;
import org.bukkit.entity.Player;
import org.bukkit.event.EventHandler;
import org.bukkit.event.Listener;
import org.bukkit.event.block.Action;
import org.bukkit.event.block.SignChangeEvent;
import org.bukkit.event.player.PlayerInteractEvent;
public class Signs implements Listener {
@EventHandler
public void onSignChange(SignChangeEvent e) {
if (e.getLine(0).equalsIgnoreCase("[shop]")) {
Block attached = e.getBlock().getRelative(0, -1, 0);
String name = e.getPlayer().getDisplayName();
if (!(attached.getType() == Material.CHEST))
e.getPlayer().sendMessage(ChatColor.RED + "Please place the shop on a chest!");
else {
if (!e.getPlayer().hasPermission("shops.create"))
e.getPlayer().sendMessage(ChatColor.RED + "You don't have permission to create a shop! (shops.create)");
else {
if (!e.getLine(1).equalsIgnoreCase("open") || (!e.getLine(1).equalsIgnoreCase("closed"))) {
e.getPlayer().sendMessage(ChatColor.RED + "You must specify if the shop is open or closed on the second line!");
} else {
Sign o = (Sign) e.getBlock().getState();
String p = o.getLine(1);
e.setLine(0, "§9[Shop]");
e.setLine(1, "§4" + name + "'s");
e.setLine(2, "§4Shop");
e.setLine(3, p);
e.getPlayer().sendMessage(ChatColor.GREEN + "Shop Created!");
e.getPlayer().playSound(e.getPlayer().getLocation(), Sound.LEVEL_UP, 10, 10);
}
}
}
}
}
@EventHandler
public void onPlayerInteract(PlayerInteractEvent e) {
if (e.getAction().equals(Action.RIGHT_CLICK_BLOCK)) {
Player p = e.getPlayer();
Block b = e.getClickedBlock();
Material m = b.getType();
if (!(m == Material.SIGN_POST)) {
return;
} else {
Sign sign = (Sign) e.getClickedBlock().getState();
if ((sign.getLine(0).equalsIgnoreCase("§9[Shop]"))) {
p.sendMessage("I right clicked the sign!");
}
}
}
}
}
您可以创建一个要与之比较的字符串列表,然后使用 List.contains
方法:
if (!Arrays.asList("open", "closed").contains(e.getLine(1).toLowerCase()) {...
您的代码无法正常工作的原因是德摩根定律
给定两个语句,A 和 B。如果您不希望 A 或 B 为真
(!A) or (!B)
不正确
(!A) and (!B)
是正确的,或者 !(A or B)
在逻辑上是等价的。
我该怎么做? 我想测试符号行 2 (1) 是否等于 "Closed" 或 "Open" 如果不是我想说请指定它是打开还是关闭它说如果我输入打开或关闭 || 在哪里是行不通的...
package me.mcmatt.shops;
import org.bukkit.ChatColor;
import org.bukkit.Material;
import org.bukkit.Sound;
import org.bukkit.block.Block;
import org.bukkit.block.Sign;
import org.bukkit.entity.Player;
import org.bukkit.event.EventHandler;
import org.bukkit.event.Listener;
import org.bukkit.event.block.Action;
import org.bukkit.event.block.SignChangeEvent;
import org.bukkit.event.player.PlayerInteractEvent;
public class Signs implements Listener {
@EventHandler
public void onSignChange(SignChangeEvent e) {
if (e.getLine(0).equalsIgnoreCase("[shop]")) {
Block attached = e.getBlock().getRelative(0, -1, 0);
String name = e.getPlayer().getDisplayName();
if (!(attached.getType() == Material.CHEST))
e.getPlayer().sendMessage(ChatColor.RED + "Please place the shop on a chest!");
else {
if (!e.getPlayer().hasPermission("shops.create"))
e.getPlayer().sendMessage(ChatColor.RED + "You don't have permission to create a shop! (shops.create)");
else {
if (!e.getLine(1).equalsIgnoreCase("open") || (!e.getLine(1).equalsIgnoreCase("closed"))) {
e.getPlayer().sendMessage(ChatColor.RED + "You must specify if the shop is open or closed on the second line!");
} else {
Sign o = (Sign) e.getBlock().getState();
String p = o.getLine(1);
e.setLine(0, "§9[Shop]");
e.setLine(1, "§4" + name + "'s");
e.setLine(2, "§4Shop");
e.setLine(3, p);
e.getPlayer().sendMessage(ChatColor.GREEN + "Shop Created!");
e.getPlayer().playSound(e.getPlayer().getLocation(), Sound.LEVEL_UP, 10, 10);
}
}
}
}
}
@EventHandler
public void onPlayerInteract(PlayerInteractEvent e) {
if (e.getAction().equals(Action.RIGHT_CLICK_BLOCK)) {
Player p = e.getPlayer();
Block b = e.getClickedBlock();
Material m = b.getType();
if (!(m == Material.SIGN_POST)) {
return;
} else {
Sign sign = (Sign) e.getClickedBlock().getState();
if ((sign.getLine(0).equalsIgnoreCase("§9[Shop]"))) {
p.sendMessage("I right clicked the sign!");
}
}
}
}
}
您可以创建一个要与之比较的字符串列表,然后使用 List.contains
方法:
if (!Arrays.asList("open", "closed").contains(e.getLine(1).toLowerCase()) {...
您的代码无法正常工作的原因是德摩根定律
给定两个语句,A 和 B。如果您不希望 A 或 B 为真
(!A) or (!B)
不正确
(!A) and (!B)
是正确的,或者 !(A or B)
在逻辑上是等价的。