映射两个对象数组，匹配属性并将特定信息存储在新数组中

Question

javascript 的新手，正在努力学习！我正在尝试通过两个对象数组进行映射，如果某个属性匹配，则将特定信息拉入一个数组。

let result;

let arrNames = [{
  name: "A"
}, {
  name: "B"
}, {
  name: "C"
}]

let arrInfo = [{
  name: "A",
  info: "AAA"
}, {
  name: "B",
  info: "BBB"
}, {
  name: "C",
  info: "ccc"
}]

如果 arrNames.name == arrInfo.name，我希望结果等于 arrInfo.info。

我尝试过的：

arrNames.map(x => {
if(arrNames.name == arrInfo.name){
   result=arrInfo.info
}

^ 这显然行不通——但我想知道 Assign 或 Filter 是否合适。

预先感谢您的帮助（很抱歉这可能是个骗局）！

Answer 1

您可以使用带有条件的地图

el.name === arrNames[index].name && el.info

表示：

if (el.name === arrNames[index].name) return el.info

let arrNames = [{
  name: "A"
}, {
  name: "B"
}, {
  name: "C"
}]

let arrInfo = [{
  name: "A",
  info: "AAA"
}, {
  name: "B",
  info: "BBB"
}, {
  name: "C",
  info: "ccc"
}]


const res = arrInfo.map((el, index) => el.name === arrNames[index].name && el.info)

console.log(res)

Answer 2

let result = [];

arrNames = [
   {name: "A"},
   {name: "B"},
   {name: "C"},
]

arrInfo = [
   {name: "A", info: "AAA"},
   {name: "B", info: "BBB"},
   {name: "C", info: "ccc"},
]

result = arrNames.map(function(_, index){
  if(arrNames[index].name === arrInfo[index].name) {
    return arrInfo[index].info
  }
})

Answer 3

您可以使用 find() inside map() 来查找元素。即使它们在两个数组中的索引不相同，这也会找到该元素。

然后使用 filter() 过滤任何 undefined 值，如果不匹配，这些值将出现。

var arrNames = [
   {name: "A"},
   {name: "B"},
   {name: "C"}
];

var arrInfo = [
   {name: "A", info: "AAA"},
   {name: "B", info: "BBB"},
   {name: "C", info: "ccc"}
];

let result = arrNames.map(x => {
  item = arrInfo.find(item => item.name === x.name);
  if (item) { 
    return item.info;
  }      
}).filter(item => item !== undefined); // Can also use filter(item => item);

console.log(result);

映射两个对象数组，匹配属性并将特定信息存储在新数组中

Map over two arrays of objects, match properties and store specific info in a new array

javascript

arrays

object

prototypejs

array.prototype.map