如何通过 HTTP GET 发送 JSON 并在 return 中获取状态码?
How can I send JSON via HTTP GET and get a status code in return?
我已经实现了一个 GetMapping,它接受一个 RequestBody 和 returns 一个状态代码:
@GetMapping(consumes = "application/json", produces = "application/json")
public ResponseEntity getAgreement(@RequestBody DataObject payload) {
Boolean found = agreementService.findSingleAgreement(payload);
if (found) {
return new ResponseEntity(HttpStatus.OK);
} else {
return new ResponseEntity(HttpStatus.NOT_FOUND);
}
}
我不想实现具有多个 RequestParam 的 GetMapping,这就是 JSON 的用途。
现在我很难测试 Get-Request,因为 ResponseEntity 要么不能被 Jackson 反序列化,要么 HttpEntity 中的 RequestBody 没有被读取:
@Test
public void testGetRequest() {
DataObject dataObject = new DataObject();
dataObject.setAgrType("A"); // more setters exist
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<DataObject> entity = new HttpEntity<>(dataObject, headers);
ResponseEntity<DataObject> answer = this.restTemplate
.withBasicAuth(username, password)
.exchange(URL, HttpMethod.GET, entity,
new ParameterizedTypeReference<ResponseEntity>() {}); // exhange's causing trouble!!
assertThat(answer.getStatusCode()).isEqualTo(HttpStatus.OK);
}
这是 Jackson 的例外情况:
org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class org.springframework.http.ResponseEntity]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `org.springframework.http.ResponseEntity` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator) at [Source: (PushbackInputStream); line: 1, column: 2]
@GetMapping
是 @RequestMapping
注释的特殊版本,充当 @RequestMapping(method = RequestMethod.GET)
的快捷方式。 consumes
对 @RequestMapping(method = RequestMethod.POST)
(或专用版本 @PostMapping
)有意义,但对 @GetMapping
没有意义。您需要使用 HTTP POST 才能使用您的 JSON 数据。
我已经实现了一个 GetMapping,它接受一个 RequestBody 和 returns 一个状态代码:
@GetMapping(consumes = "application/json", produces = "application/json")
public ResponseEntity getAgreement(@RequestBody DataObject payload) {
Boolean found = agreementService.findSingleAgreement(payload);
if (found) {
return new ResponseEntity(HttpStatus.OK);
} else {
return new ResponseEntity(HttpStatus.NOT_FOUND);
}
}
我不想实现具有多个 RequestParam 的 GetMapping,这就是 JSON 的用途。
现在我很难测试 Get-Request,因为 ResponseEntity 要么不能被 Jackson 反序列化,要么 HttpEntity 中的 RequestBody 没有被读取:
@Test
public void testGetRequest() {
DataObject dataObject = new DataObject();
dataObject.setAgrType("A"); // more setters exist
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<DataObject> entity = new HttpEntity<>(dataObject, headers);
ResponseEntity<DataObject> answer = this.restTemplate
.withBasicAuth(username, password)
.exchange(URL, HttpMethod.GET, entity,
new ParameterizedTypeReference<ResponseEntity>() {}); // exhange's causing trouble!!
assertThat(answer.getStatusCode()).isEqualTo(HttpStatus.OK);
}
这是 Jackson 的例外情况:
org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class org.springframework.http.ResponseEntity]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `org.springframework.http.ResponseEntity` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator) at [Source: (PushbackInputStream); line: 1, column: 2]
@GetMapping
是 @RequestMapping
注释的特殊版本,充当 @RequestMapping(method = RequestMethod.GET)
的快捷方式。 consumes
对 @RequestMapping(method = RequestMethod.POST)
(或专用版本 @PostMapping
)有意义,但对 @GetMapping
没有意义。您需要使用 HTTP POST 才能使用您的 JSON 数据。