file_get_contents() 期望参数 1 是有效路径
file_get_contents() expects parameter 1 to be a valid path
我的图片正在成功上传到 images/news。我现在想将该图像保存在数据库中。但它一直给我上述错误。我的模型查询是正确的,因为我用它来插入其他数据并且它有效。
如何在用户点击提交后将图像保存到数据库中?
我的控制器:
function news()
{
$config = array(
'upload_path' => "./images/news",
'allowed_types' => "gif|jpg|png|jpeg|JPG",
'overwrite' =>False,
'max_size' => "2048000",
'max_height' => "768",
'max_width' => "1024"
);
$this->load->library('upload', $config);
$this->load->helper(array('form', 'url'));
if($this->upload->do_upload())
{
$data = array('upload_data' => $this->upload->data());
$this->load->view('manage_news',$data);
}
else
{
$message2 = "Please choose another file type. gif,jpg,png,jpeg,pdf ";
echo "<script type='text/javascript'>alert('$message2'); </script>";
redirect('resetPasswordController/add_news', 'refresh');
}
$this->db->trans_start();
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data )
);
$this->load->model('users_model');
$this->users_model->insert($data);
$this->db->trans_complete();
$this->db->trans_complete();
redirect('resetPasswordController/manage_news', 'refresh');
}
我的看法:
<?php echo form_open_multipart('resetPasswordController/news');?>
<label>Image</label>
<input name = "userfile" type="file" />
我的模特:
function insert($data){
$this->db->insert('news',$data);
return $this->db->insert_id();
}
$data 包含数组值,你必须使用 upload_data
例如:
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data )
);
将此更改为
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data['upload_data'] )
);
或
可以直接使用上传数据功能
$data = array(
'image' => file_get_contents( $this->upload->data())
);
我的图片正在成功上传到 images/news。我现在想将该图像保存在数据库中。但它一直给我上述错误。我的模型查询是正确的,因为我用它来插入其他数据并且它有效。
如何在用户点击提交后将图像保存到数据库中?
我的控制器:
function news()
{
$config = array(
'upload_path' => "./images/news",
'allowed_types' => "gif|jpg|png|jpeg|JPG",
'overwrite' =>False,
'max_size' => "2048000",
'max_height' => "768",
'max_width' => "1024"
);
$this->load->library('upload', $config);
$this->load->helper(array('form', 'url'));
if($this->upload->do_upload())
{
$data = array('upload_data' => $this->upload->data());
$this->load->view('manage_news',$data);
}
else
{
$message2 = "Please choose another file type. gif,jpg,png,jpeg,pdf ";
echo "<script type='text/javascript'>alert('$message2'); </script>";
redirect('resetPasswordController/add_news', 'refresh');
}
$this->db->trans_start();
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data )
);
$this->load->model('users_model');
$this->users_model->insert($data);
$this->db->trans_complete();
$this->db->trans_complete();
redirect('resetPasswordController/manage_news', 'refresh');
}
我的看法:
<?php echo form_open_multipart('resetPasswordController/news');?>
<label>Image</label>
<input name = "userfile" type="file" />
我的模特:
function insert($data){
$this->db->insert('news',$data);
return $this->db->insert_id();
}
$data 包含数组值,你必须使用 upload_data
例如:
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data )
);
将此更改为
$data = array('upload_data' => $this->upload->data());
$data = array(
'image' => file_get_contents( $data['upload_data'] )
);
或
可以直接使用上传数据功能
$data = array(
'image' => file_get_contents( $this->upload->data())
);