python str对象不支持项目赋值

Question

我正在尝试将列表中的乱序词设置回我创建的列表，该列表来自 split。我尝试阅读此处的一些解决方案，我认为这是因为您无法更改列表中的字符串？

如果我错了，我不确定是否纠正我:(。the sentence[i] = temp_word 给出了错误。提前致谢:)

class WordScramble:
def __init__(self):
    self.user_input = input("Please give me a sentence: ")

def scramble(self):
    # print what was input
    print("The user input was: ", self.user_input)

    # first scramble is just one word
    print(self.user_input[0] + self.user_input[2] + self.user_input[1] + self.user_input[3:])

    # reverse two indices
    # particularly good to use is to switch the first two
    # and the last two
    # this only makes sense if you have a world that is longer than 3


    # now try to scramble one sentence
    sentence = self.user_input.strip().split(" ")

    for i, word in enumerate(sentence):
        if len(word) > 3:
            temp_word = list(word)
            if ',' in temp_word:
                temp = temp_word[1]
                temp_word[1] = temp_word[-3]
                temp_word[-3] = temp

            else:
                temp = temp_word[1]
                temp_word[1] = temp_word[2]
                temp_word[2] = temp

            temp_word = ''.join(temp_word)
            sentence[i] = temp_word
        sentence = ''.join(sentence)
        print(sentence)




    #print(" ".join(sentence))

    # do just words first, then you can move on to work on
    # punctuation

word_scrambler = WordScramble()
word_scrambler.scramble()

Answer 1

因为在 for 循环中你写了：

sentence = ''.join(sentence)

因此，在第二次迭代中，'sentence' 变量现在是一个字符串，而在 python 中，字符串不支持项目分配，因为它们是不可变变量。我认为你的意思是将它从 for 循环中取出来打印最后一句话。

python str对象不支持项目赋值

python str object does not support item assignment

python

string

list

loops

scramble