Python: 创建一个计算文本文件中特定单词的函数

Question

我想创建一个函数，returns 文本文件中特定单词的字数计数值。

这是我目前拥有的：

def Word_Counter(Text_File, Word):

    Data = open(Text_File, 'r').read().lower()

    count = Data.count(Word)


    print(Word, "; ", count)

Word_Counter('Example.txt', "the")

哪个returns："the ; 35"

这正是我想要它做的。但是，如果我想测试文本中的一系列单词怎么办？我想要列表或字典中的单词（键）和值。有什么方法可以不使用模块来做到这一点？

假设我使用以下单词列表测试函数：[time, when, left, I, do, an, who, what, sometimes]。

我想要的结果是这样的：

Word Counts = {'time': 1, 'when': 4, 'left': 0, 'I': 5, 'do': 2, 'an': 0, 'who': 1, 'what': 3, 'sometimes': 1}

我已经能够创建一个字典，它对每个单词进行单词计数，如下例所示。

wordfreq = {}
for word in words.replace(',', ' ').split():
   wordfreq[word] = wordfreq.setdefault(word, 0) + 1

我想做一个类似的风格，但只针对特定的词，有什么建议吗？

Answer 1

根据您提供的代码，我没有对此进行测试。

def Word_Counter(Text_File, word_list):

        Data = open(Text_File, 'r').read().lower()
        output = {}
        for word in word_list:
           output[word] = Data.count(Word)

或者你可以这样做

text = open("sample.txt", "r") 

# Create an empty dictionary 
d = dict() 

# Loop through each line of the file 
for line in text: 
    # Remove the leading spaces and newline character 
    line = line.strip() 

    # Convert the characters in line to  
    # lowercase to avoid case mismatch 
    line = line.lower() 

    # Split the line into words 
    words = line.split(" ") 

    # Iterate over each word in line 
    for word in words: 
        # Check if the word is already in dictionary 
        if word in d: 
            # Increment count of word by 1 
            d[word] = d[word] + 1
        else: 
            # Add the word to dictionary with count 1 
            d[word] = 1

Answer 2

更新

尝试以下操作：

keywords = ['the', 'that']
worddict = {}

with open('out.txt', 'r') as f:
    text = f.read().split(' ')  # or f.read().split(',')

for word in text:
    worddict[word] = worddict[word]+1 if word in worddict else 1

print([{x, worddict[x]} for x in keywords])

Python: 创建一个计算文本文件中特定单词的函数

Python: Creating a function counting specific words in a textfile

python

string

list

dictionary

word-count

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