Custom URL Scheme Error : This app is not allowed to query for scheme

Custom URL Scheme Error : This app is not allowed to query for scheme

我有 2 个应用程序,一个客户端和一个服务器。我正在尝试使用 URL 方案

在 ios 应用程序之间进行应用程序间通信

(我已参考此 https://developer.apple.com/documentation/uikit/inter-process_communication/allowing_apps_and_websites_to_link_to_your_content/defining_a_custom_url_scheme_for_your_app 作为指南)

这是客户端的plist

<dict>
    <key>CFBundleDevelopmentRegion</key>
    <string>$(DEVELOPMENT_LANGUAGE)</string>
    <key>CFBundleExecutable</key>
    <string>$(EXECUTABLE_NAME)</string>
    <key>CFBundleIdentifier</key>
    <string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>
    <key>CFBundleInfoDictionaryVersion</key>
    <string>6.0</string>
    <key>CFBundleName</key>
    <string>$(PRODUCT_NAME)</string>
    <key>CFBundlePackageType</key>
    <string>APPL</string>
    <key>CFBundleShortVersionString</key>
    <string>1.0</string>
    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleTypeRole</key>
            <string>Viewer</string>
            <key>CFBundleURLName</key>
            <string>com.test.serverendapp</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>serverendapp</string>
            </array>
        </dict>
    </array>
    <key>CFBundleVersion</key>
    <string>1</string>
    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>com.test.serverendapp</string>
    </array>
    <key>LSRequiresIPhoneOS</key>
    <true/>
    <key>UILaunchStoryboardName</key>
    <string>LaunchScreen</string>
    <key>UIMainStoryboardFile</key>
    <string>Main</string>
    <key>UIRequiredDeviceCapabilities</key>
    <array>
        <string>armv7</string>
    </array>
    <key>UISupportedInterfaceOrientations</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
    <key>UISupportedInterfaceOrientations~ipad</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationPortraitUpsideDown</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
</dict>
</plist>

代码 iOS 结束

@IBAction func tapToClient(){
        let urlsrting = "com.test.serverEndApp://requestInfo?userID='22'"
        let url = URL(string: urlsrting)!
        if UIApplication.shared.canOpenURL(url){

            if #available(iOS 10.0, *) {
                UIApplication.shared.open(url, options: [:]) { (success) in
                    print(" this is \(success)")
                }

            } else {
                UIApplication.shared.openURL(url)
            }
        }else{

            let alertController = UIAlertController(title: "Error", message:
                "There is no such server app here", preferredStyle: .alert)
            alertController.addAction(UIAlertAction(title: "Dismiss", style: .default))

            self.present(alertController, animated: true, completion: nil)

        }
    }

服务器端

plist

<dict>
    <key>CFBundleDevelopmentRegion</key>
    <string>$(DEVELOPMENT_LANGUAGE)</string>
    <key>CFBundleExecutable</key>
    <string>$(EXECUTABLE_NAME)</string>
    <key>CFBundleIdentifier</key>
    <string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>
    <key>CFBundleInfoDictionaryVersion</key>
    <string>6.0</string>
    <key>CFBundleName</key>
    <string>$(PRODUCT_NAME)</string>
    <key>CFBundlePackageType</key>
    <string>APPL</string>
    <key>CFBundleShortVersionString</key>
    <string>1.0</string>
    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleTypeRole</key>
            <string>Viewer</string>
            <key>CFBundleURLName</key>
            <string>com.test.clientendapp</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>clientendapp</string>
            </array>
        </dict>
    </array>
    <key>CFBundleVersion</key>
    <string>1</string>
    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>com.test.clientendapp</string>
    </array>
    <key>LSRequiresIPhoneOS</key>
    <true/>
    <key>UILaunchStoryboardName</key>
    <string>LaunchScreen</string>
    <key>UIMainStoryboardFile</key>
    <string>Main</string>
    <key>UIRequiredDeviceCapabilities</key>
    <array>
        <string>armv7</string>
    </array>
    <key>UISupportedInterfaceOrientations</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
    <key>UISupportedInterfaceOrientations~ipad</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationPortraitUpsideDown</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
</dict>
</plist>

代码

 @IBAction func tapToServer(){
        let urlsrting = "com.test.clientEndApp://provideInfo?username='Debanjan'"
        let url = URL(string: urlsrting)!
        if UIApplication.shared.canOpenURL(url){
            if #available(iOS 10.0, *) {
                UIApplication.shared.open(url, options: [:]) { (success) in
                    print(" this is \(success)")
                }

            } else {
                UIApplication.shared.openURL(url)
            }
        }else{
            let alertController = UIAlertController(title: "Error", message:
                "There is no such client app here", preferredStyle: .alert)
            alertController.addAction(UIAlertAction(title: "Dismiss", style: .default))

            self.present(alertController, animated: true, completion: nil)

        }
    }
}

我从他们两个那里得到的都是

-canOpenURL: failed for URL: "com.test.clientEndApp://provideInfo?username='Debanjan'" - error: "This app is not allowed to query for scheme com.test.clientendapp"

-canOpenURL: failed for URL: "com.test.serverEndApp://requestInfo?userID='22'" - error: "This app is not allowed to query for scheme com.test.serverendapp"

我已经执行了所有步骤,但仍处于这种状态。帮助我意识到我做错了什么

我是运行它在iPhone8iOS12.2模拟器上,在xcode12.2

如果你注册了,你就是在做相反的事情:

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>com.test.clientEndApp</string>
</array>

你应该调用这个方案

let urlsrting = "com.test.clientEndApp://provideInfo?username='Debanjan'"

LSApplicationQueriesSchemes

中缺少 com.test.

所以感谢@Lu_指出我的错误

积分: 1.客户端应用程序将具有服务器应用程序的方案,反之亦然 2. LS应该有一个完整的名字,没有这样的com.test或者什么不是