我如何创建一个 void 函数,在 13 日星期五列出下一个 13
How can I create a void function that lists next 13 Friday on 13th
伙计们,我想在 13 日创建一个即将到来的 13 个星期五的列表
我该怎么做?
我试了一年:
public static void getFridayThirteen() {
for (int i = 1; i <= 365; i++) {
if (Calendar.FRIDAY == 13) {
fridayThirteen = i++;
System.out.println("Test" + fridayThirteen);
}
}
但输出中没有任何内容。
您可以这样做的一种方法是:
LocalDate ld = LocalDate.now(); // or the LocalDate.now(ZoneId) overload
int count = 0;
// first set the date to the next Friday first...
ld = ld.with(TemporalAdjusters.next(DayOfWeek.FRIDAY));
// this will find 10 such dates
while (count < 10) {
if (isFriday13(ld)) { // implementation shown below
count++;
System.out.println(ld);
}
ld = ld.plusDays(7); // this set ld to be the next Friday
}
isFriday13
声明为:
private static boolean isFriday13(LocalDate ld) {
return ld.getDayOfMonth() == 13 && ld.getDayOfWeek() == DayOfWeek.FRIDAY;
}
伙计们,我想在 13 日创建一个即将到来的 13 个星期五的列表 我该怎么做?
我试了一年:
public static void getFridayThirteen() {
for (int i = 1; i <= 365; i++) {
if (Calendar.FRIDAY == 13) {
fridayThirteen = i++;
System.out.println("Test" + fridayThirteen);
}
}
但输出中没有任何内容。
您可以这样做的一种方法是:
LocalDate ld = LocalDate.now(); // or the LocalDate.now(ZoneId) overload
int count = 0;
// first set the date to the next Friday first...
ld = ld.with(TemporalAdjusters.next(DayOfWeek.FRIDAY));
// this will find 10 such dates
while (count < 10) {
if (isFriday13(ld)) { // implementation shown below
count++;
System.out.println(ld);
}
ld = ld.plusDays(7); // this set ld to be the next Friday
}
isFriday13
声明为:
private static boolean isFriday13(LocalDate ld) {
return ld.getDayOfMonth() == 13 && ld.getDayOfWeek() == DayOfWeek.FRIDAY;
}