SQL 为符号 in/sign 转出数据，按应用程序
SQL Pivoting data for sign in/sign out, by application
我有一个审计日志，用于存储在整个系统中一个或多个连接的应用程序上发生的事件。
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
SELECT
l.RecordedOn, s.FirstName + ' ' + s.LastName + ' (#' + CAST(l.StaffIDAffected AS VARCHAR(MAX)) + ')' AS StaffName,
InOut = CASE WHEN (l.Type = 'AUS') THEN 'Sign In' WHEN (l.Type = 'AUSO') THEN 'Sign Out' END,
a.Name AS ApplicationName, l.ApplicationID
FROM Logs l
LEFT JOIN OtherDB.dbo.Staff s ON (s.ID = l.StaffIDAffected)
LEFT JOIN Applications a ON (l.ApplicationID = a.ID)
WHERE
l.Type in ('AUS','AUSO') AND
l.StaffIDAffected = @staffID AND
l.RecordedOn BETWEEN @startDate AND @endDate
ORDER BY s.FirstName + ' ' + s.LastName, l.RecordedOn ASC
本returns以下数据：
RecordedOn StaffName InOut ApplicationName
ApplicationID
2015-06-01 13:56:32.490 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:05:02.900 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:06:01.470 Joel Smith (#4) Sign Out NULL 0
2015-06-01 14:22:57.000 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:23:04.170 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:36:10.293 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:47:38.993 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:55:56.297 Joel Smith (#4) Sign In Admin Website 4
2015-06-01 14:56:33.107 Joel Smith (#4) Sign In Panel 2
2015-06-01 14:56:43.783 Joel Smith (#4) Sign Out NULL 0
2015-06-01 15:00:03.950 Joel Smith (#4) Sign In Panel 2
2015-06-01 15:06:33.403 Joel Smith (#4) Sign In Admin Website 4
2015-06-01 15:06:45.843 Joel Smith (#4) Sign Out Admin Website 4
2015-06-01 15:23:57.543 Joel Smith (#4) Sign In Panel 2
我想要的格式如下。我将空应用程序名称合并为 'General' 并将空应用程序 ID 合并为 -1。 （NULL 值会随着时间的推移而消失，但现在需要稍微优雅地处理它们）。
StaffName ApplicationName ApplicationID SignIn SignOut
Joel Smith (#4) General -1 2015-06-01 13:56:32.490 NULL
Joel Smith (#4) General -1 2015-06-01 14:05:02.900 2015-06-01 14:06:01.470
Joel Smith (#4) General -1 2015-06-01 14:22:57.000 NULL
Joel Smith (#4) General -1 2015-06-01 14:23:04.170 NULL
Joel Smith (#4) General -1 2015-06-01 14:36:10.293 NULL
Joel Smith (#4) General -1 2015-06-01 14:47:38.993 2015-06-01 14:56:43.783
Joel Smith (#4) Admin Website 4 2015-06-01 14:55:56.297 NULL
Joel Smith (#4) Panel 2 2015-06-01 14:56:33.107 NULL
Joel Smith (#4) Panel 2 2015-06-01 15:00:03.950 NULL
Joel Smith (#4) Admin Website 4 2015-06-01 15:06:33.403 2015-06-01 15:06:45.843
Joel Smith (#4) Panel 2 2015-06-01 15:23:57.543 NULL
请注意，它应该按应用程序 Name/Application ID 分隔 login/logout 次。
这是我目前拥有的，但缺少一些东西:
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
SELECT
StaffName,
ApplicationName,
ApplicationID,
SignIn,
SignOut
FROM
(
SELECT
l.RecordedOn,
s.FirstName + ' ' + s.LastName + ' (#' + CAST(l.StaffIDAffected AS VARCHAR(MAX)) + ')' AS StaffName,
InOut = CASE WHEN (l.Type = 'AUS') THEN 'SignIn' WHEN (l.Type = 'AUSO') THEN 'SignOut' END,
COALESCE(a.Name, 'General') AS ApplicationName,
COALESCE(l.ApplicationID, -1) AS ApplicationID
FROM Logs l
LEFT JOIN OtherDB.dbo.Staff s ON (s.ID = l.StaffIDAffected)
LEFT JOIN Applications a ON (l.ApplicationID = a.ID)
WHERE
l.Type in ('AUS','AUSO') AND
l.StaffIDAffected = @staffID AND
l.RecordedOn BETWEEN @startDate AND @endDate
--ORDER BY s.FirstName + ' ' + s.LastName, l.RecordedOn ASC
) p
PIVOT
(
MIN(RecordedOn)
FOR InOut IN ([SignIn], [SignOut])
) pvt
此代码returns以下数据：
StaffName ApplicationName ApplicationID SignIn SignOut
Joel Smith (#4) Admin Website 4 2015-06-01 14:55:56.297 2015-06-01 15:06:45.843
Joel Smith (#4) General 0 2015-06-01 13:56:32.490 2015-06-01 14:06:01.470
Joel Smith (#4) Panel 2 2015-06-01 14:56:33.107 NULL
我做错了什么？我正在使用 SQL 服务器 2012/2014。
EDIT 我也试过没有一个有趣的结果的枢轴：
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
;WITH cte1 AS
(
SELECT *
, ROW_NUMBER() OVER
(PARTITION BY StaffIDAffected, CAST(RecordedOn AS DATE) ORDER BY RecordedOn)
AS num
,CASE WHEN ([Type] = 'AUS') THEN 'Sign In' WHEN ([Type] = 'AUSO') THEN 'Sign Out' END AS [Status]
FROM Logs
WHERE [Type] IN ('AUS','AUSO')
AND StaffIDAffected = @staffID
AND RecordedOn BETWEEN @startDate AND @endDate
)
SELECT l1.StaffIDAffected
, l1.RecordedOn [SignIn]
, l2.RecordedOn [SignOut]
FROM cte1 l1
left outer JOIN
cte1 l2 ON
l2.StaffIDAffected = l1.StaffIDAffected
AND CAST(l2.RecordedOn AS DATE) = CAST(l1.RecordedOn AS DATE)
AND l2.num = l1.num + 1
WHERE l1.status = 'Sign In'
AND (l2.Status IS NULL OR l2.Status = 'Sign Out')
请注意，这个不包括应用程序，因为我只是想通过 NULL 应用程序来获取正确的值 name/ID...
4 2015-06-01 14:05:02.900 2015-06-01 14:06:01.470
4 2015-06-01 14:56:33.107 2015-06-01 14:56:43.783
4 2015-06-01 15:06:33.403 2015-06-01 15:06:45.843
4 2015-06-01 16:00:35.477 2015-06-01 16:01:47.703
4 2015-06-01 16:02:20.487 2015-06-01 16:03:34.827
4 2015-06-01 16:09:14.353 2015-06-01 16:09:22.213
4 2015-06-01 16:13:26.377 2015-06-01 16:14:01.560
因为我们没有fiddle我只能建议。 Pivot 将按子查询中不在 aggregation 部分和 spreading 部分中的列分组，即它将按 StaffName, ApplicationName, ApplicationID 分组。所以你最终会得到几行，其中有这些列的不同组合。
现在您想要所有 login 行最接近 logout 行。如果这是真的，那么你可以这样做：
select c1.ApplicationID,
c1.ApplicationName,
c1.StaffName,
c1.RecordedOn as SignIn,
oa.RecordedOn as SignOut
from cte1 c1
outer apply( select top 1 RecordedOn from cte2 c2
where c1.ApplicationID = c2.ApplicationID and
c1.StaffName = c2.StaffName and
c2.RecordedOn > c1.RecordedOn and
c2.InOut = 'Sign Out' and
c1.num + 1 = c2.num
order by c2.RecordedOn) oa
where c1.InOut = 'Sign In'
我有一个审计日志，用于存储在整个系统中一个或多个连接的应用程序上发生的事件。
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
SELECT
l.RecordedOn, s.FirstName + ' ' + s.LastName + ' (#' + CAST(l.StaffIDAffected AS VARCHAR(MAX)) + ')' AS StaffName,
InOut = CASE WHEN (l.Type = 'AUS') THEN 'Sign In' WHEN (l.Type = 'AUSO') THEN 'Sign Out' END,
a.Name AS ApplicationName, l.ApplicationID
FROM Logs l
LEFT JOIN OtherDB.dbo.Staff s ON (s.ID = l.StaffIDAffected)
LEFT JOIN Applications a ON (l.ApplicationID = a.ID)
WHERE
l.Type in ('AUS','AUSO') AND
l.StaffIDAffected = @staffID AND
l.RecordedOn BETWEEN @startDate AND @endDate
ORDER BY s.FirstName + ' ' + s.LastName, l.RecordedOn ASC
本returns以下数据：
RecordedOn StaffName InOut ApplicationName
ApplicationID
2015-06-01 13:56:32.490 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:05:02.900 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:06:01.470 Joel Smith (#4) Sign Out NULL 0
2015-06-01 14:22:57.000 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:23:04.170 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:36:10.293 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:47:38.993 Joel Smith (#4) Sign In NULL 0
2015-06-01 14:55:56.297 Joel Smith (#4) Sign In Admin Website 4
2015-06-01 14:56:33.107 Joel Smith (#4) Sign In Panel 2
2015-06-01 14:56:43.783 Joel Smith (#4) Sign Out NULL 0
2015-06-01 15:00:03.950 Joel Smith (#4) Sign In Panel 2
2015-06-01 15:06:33.403 Joel Smith (#4) Sign In Admin Website 4
2015-06-01 15:06:45.843 Joel Smith (#4) Sign Out Admin Website 4
2015-06-01 15:23:57.543 Joel Smith (#4) Sign In Panel 2
我想要的格式如下。我将空应用程序名称合并为 'General' 并将空应用程序 ID 合并为 -1。 （NULL 值会随着时间的推移而消失，但现在需要稍微优雅地处理它们）。
StaffName ApplicationName ApplicationID SignIn SignOut
Joel Smith (#4) General -1 2015-06-01 13:56:32.490 NULL
Joel Smith (#4) General -1 2015-06-01 14:05:02.900 2015-06-01 14:06:01.470
Joel Smith (#4) General -1 2015-06-01 14:22:57.000 NULL
Joel Smith (#4) General -1 2015-06-01 14:23:04.170 NULL
Joel Smith (#4) General -1 2015-06-01 14:36:10.293 NULL
Joel Smith (#4) General -1 2015-06-01 14:47:38.993 2015-06-01 14:56:43.783
Joel Smith (#4) Admin Website 4 2015-06-01 14:55:56.297 NULL
Joel Smith (#4) Panel 2 2015-06-01 14:56:33.107 NULL
Joel Smith (#4) Panel 2 2015-06-01 15:00:03.950 NULL
Joel Smith (#4) Admin Website 4 2015-06-01 15:06:33.403 2015-06-01 15:06:45.843
Joel Smith (#4) Panel 2 2015-06-01 15:23:57.543 NULL
请注意，它应该按应用程序 Name/Application ID 分隔 login/logout 次。
这是我目前拥有的，但缺少一些东西:
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
SELECT
StaffName,
ApplicationName,
ApplicationID,
SignIn,
SignOut
FROM
(
SELECT
l.RecordedOn,
s.FirstName + ' ' + s.LastName + ' (#' + CAST(l.StaffIDAffected AS VARCHAR(MAX)) + ')' AS StaffName,
InOut = CASE WHEN (l.Type = 'AUS') THEN 'SignIn' WHEN (l.Type = 'AUSO') THEN 'SignOut' END,
COALESCE(a.Name, 'General') AS ApplicationName,
COALESCE(l.ApplicationID, -1) AS ApplicationID
FROM Logs l
LEFT JOIN OtherDB.dbo.Staff s ON (s.ID = l.StaffIDAffected)
LEFT JOIN Applications a ON (l.ApplicationID = a.ID)
WHERE
l.Type in ('AUS','AUSO') AND
l.StaffIDAffected = @staffID AND
l.RecordedOn BETWEEN @startDate AND @endDate
--ORDER BY s.FirstName + ' ' + s.LastName, l.RecordedOn ASC
) p
PIVOT
(
MIN(RecordedOn)
FOR InOut IN ([SignIn], [SignOut])
) pvt
此代码returns以下数据：
StaffName ApplicationName ApplicationID SignIn SignOut
Joel Smith (#4) Admin Website 4 2015-06-01 14:55:56.297 2015-06-01 15:06:45.843
Joel Smith (#4) General 0 2015-06-01 13:56:32.490 2015-06-01 14:06:01.470
Joel Smith (#4) Panel 2 2015-06-01 14:56:33.107 NULL
我做错了什么？我正在使用 SQL 服务器 2012/2014。
EDIT 我也试过没有一个有趣的结果的枢轴：
DECLARE @startDate DATETIME;
DECLARE @endDate DATETIME;
DECLARE @staffID INT;
SET @staffID = 4;
SELECT
@startDate = dbo.Date(COALESCE(@startDate, DATEADD(day, -1, GETUTCDATE()))),
@endDate = dbo.EndOfDay(COALESCE(@endDate, GETUTCDATE()))
;WITH cte1 AS
(
SELECT *
, ROW_NUMBER() OVER
(PARTITION BY StaffIDAffected, CAST(RecordedOn AS DATE) ORDER BY RecordedOn)
AS num
,CASE WHEN ([Type] = 'AUS') THEN 'Sign In' WHEN ([Type] = 'AUSO') THEN 'Sign Out' END AS [Status]
FROM Logs
WHERE [Type] IN ('AUS','AUSO')
AND StaffIDAffected = @staffID
AND RecordedOn BETWEEN @startDate AND @endDate
)
SELECT l1.StaffIDAffected
, l1.RecordedOn [SignIn]
, l2.RecordedOn [SignOut]
FROM cte1 l1
left outer JOIN
cte1 l2 ON
l2.StaffIDAffected = l1.StaffIDAffected
AND CAST(l2.RecordedOn AS DATE) = CAST(l1.RecordedOn AS DATE)
AND l2.num = l1.num + 1
WHERE l1.status = 'Sign In'
AND (l2.Status IS NULL OR l2.Status = 'Sign Out')
请注意，这个不包括应用程序，因为我只是想通过 NULL 应用程序来获取正确的值 name/ID...
4 2015-06-01 14:05:02.900 2015-06-01 14:06:01.470
4 2015-06-01 14:56:33.107 2015-06-01 14:56:43.783
4 2015-06-01 15:06:33.403 2015-06-01 15:06:45.843
4 2015-06-01 16:00:35.477 2015-06-01 16:01:47.703
4 2015-06-01 16:02:20.487 2015-06-01 16:03:34.827
4 2015-06-01 16:09:14.353 2015-06-01 16:09:22.213
4 2015-06-01 16:13:26.377 2015-06-01 16:14:01.560
因为我们没有fiddle我只能建议。 Pivot 将按子查询中不在 aggregation 部分和 spreading 部分中的列分组，即它将按 StaffName, ApplicationName, ApplicationID 分组。所以你最终会得到几行，其中有这些列的不同组合。
现在您想要所有 login 行最接近 logout 行。如果这是真的，那么你可以这样做：
select c1.ApplicationID,
c1.ApplicationName,
c1.StaffName,
c1.RecordedOn as SignIn,
oa.RecordedOn as SignOut
from cte1 c1
outer apply( select top 1 RecordedOn from cte2 c2
where c1.ApplicationID = c2.ApplicationID and
c1.StaffName = c2.StaffName and
c2.RecordedOn > c1.RecordedOn and
c2.InOut = 'Sign Out' and
c1.num + 1 = c2.num
order by c2.RecordedOn) oa
where c1.InOut = 'Sign In'