从 API 结果中解析 JSON

Question

我正在使用 RUST 和 Reqwest 从 API 中调用以下响应：

Shell:

Ok("{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":68.0464}\n"{\"SETTLEMENTDATE\":\"2019-10-24T12:55:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":67.4408}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:00:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.2918}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:05:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":98.1406}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:10:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.4789}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:15:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":90.2434}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:20:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":89.8617}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:25:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":97.2639}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:30:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":100.493}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:35:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":93.7984}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:40:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":85.1182}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:45:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":91.4173}\n\n",
)

我想解析这个输出，只打印第一个数组中的 'RRP.DISPATCHPRICE0' 值（下图 BOLD 中的数字）：

好的("{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\" :68.0464}\n" ...

我对 RUST 还是很陌生，正在努力弄清楚我应该如何最好地实现这一目标。社区中的任何人都可以帮忙 recommendations/help.

我尝试了什么：

我一直在使用以下代码：

extern crate serde_json;

use serde_json::Value;

fn main() {
    let data: Value = serde_json::from_str(
//          Ok(
           "{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":68.0464}\n"
//           {\"SETTLEMENTDATE\":\"2019-10-24T12:55:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":67.4408}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:00:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.2918}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:05:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":98.1406}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:10:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.4789}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:15:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":90.2434}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:20:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":89.8617}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:25:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":97.2639}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:30:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":100.493}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:35:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":93.7984}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:40:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":85.1182}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:45:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":91.4173}\n\n",
//            )
    )
    .unwrap();



    println!("data: {:?}", data);
    let obj = data.as_object().unwrap();
    let RRP = obj.get("RRP.DISPATCHPRICE0").unwrap();

    println!("Value: {}", RRP);
}

上面打印出我想要的数字并且工作得很好但是当我在 'Response'.

的其余部分发表评论时我无法让它工作

请帮忙！ :)

Answer 1

您的整个字符串无效JSON，因为它包含多个对象。您可以通过使用 StreamDeserializer 一个一个地提取对象来绕过它：

for value in Deserializer::from_str (data).into_iter::<Value>() {
    println!("value: {:?}", value.unwrap());
}

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从 API 结果中解析 JSON

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