Yii2框架的右连接

Question

查看

<?php 
$url = Yii::$app->urlManager->createUrl(['admin/sale/prduct']);
?>

视图页面中的脚本代码通过 GET

发送 id

视图页面中的脚本

<script>

function ddlcategor(id){
$.ajax({
 type:'GET',
url:'<?=$url?>',
data:{id:id},
success: function(data){
$("#test").html(data);
}
});
}

</script>

控制器文档 !

控制器

<?php

public function actionProduct($id){
    $products = Yii::db->createCommand('select products.* from products right join (select * from product_category where product_category.cat_pro_id ='.$id.') as t on(products.id = t.product_id)')->queryAll();

$option ='';
echo "<option>select ...</option>";
foreach($products  as $value){
  $option.="<option value=$value->id>$value->title</option>";
}

return $option;

}

?>

错误

PHP Notice - yii\base\ErrorException typing to get property of non-object

Answer 1

Yii::$app->db->createCommand()returns数组。每行都是一个包含列名和值的关联数组。如果选择 returns 什么都没有，将收到一个 空数组 。

Yii::$app->db->createCommand()->queryAll();

在您的示例中 $value 不是 objact。它是数组：

$products = Yii::db->createCommand('select products.* from products right join (select * from product_category where product_category.cat_pro_id ='.$id.') as t on(products.id = t.product_id)')->queryAll();

$option ='';
//No needed in this variant
//echo "<option>select ...</option>";
If(!empty($products)){
   foreach($products  as $value){
      $option.="<option value=$value['id']>$value['title']</option>";
   }
}else{
    $option.= "<option selected disabled>No results!</option>"
}
return $option;

要调试 ajax 结果，我建议使用 https://www.getpostman.com/ 使用此服务，您可以简单地跟踪 url 返回的结果和错误粘贴到 ajax。

Answer 2

试试这个：

public function actionProduct($id){
      $commands = Yii::$app->getDb();
      $products = $commands->createCommand('select products.* from products right join (select * from product_category where product_category.cat_pro_id ='.$id.') as t on(products.id = t.product_id)')->queryAll();    
        $option ='';
        echo "<option>select ...</option>";
        foreach($products  as $value){
          $option.="<option value=$value['id']>$value['title']</option>";
        }    
    return $option;    
    }

Yii2框架的右连接

right join of Yii2 framework

right-join

yii2

查看

视图页面中的脚本

控制器

错误