XML 为继承的对象序列化 C#

Question

我有以下 XML 场景：

<al2:Dispatch xmlns:al1="al:1.0.0" xmlns:al2="al:2.0.0">

    <al2:MsgIdentificator>0001</al2:MsgIdentificator>

    ..

    <al1:DispatchReceiverGroup>

        <al2:Receiver>

            <al1:ANumberIdentificator>100001</al1:ANumberIdentificator>
            <al1:BNumberIdentificator>1000000001</al1:BNumberIdentificator>

        </al2:Receiver>

    </al1:DispatchReceiverGroup>

</al2:Dispatch>

所以我的模型如下：

    [Serializable]
    [XmlRoot(Namespace = "al:2.0.0", ElementName = "Dispatch")]
    public class BatchDistribution
    {
        [XmlElement(Namespace = "al:2.0.0", ElementName = "MsgIdentificator")]
        public string MessageIdentificator { get; set; }

        //CONFUSED HERE
        [XmlArray(Namespace = "al:1.0.0", ElementName = "DispatchReceiverGroup")]
        [XmlArrayItem(Namespace = "al:2.0.0", ElementName = "Receiver")]
        public List<DistributionReceiver> DistributionRecievers { get; set; }    
    }
}

所以我想要可选数量的 ANumberIdentificator 和 BNumberIdentificator 元素。为此，我做了一个BaseClassDistributionReceiver，由DistributionReceiverA和DistributionReceiverB继承，如下：

    [Serializable]
    public class DistributionReceiver
    {
        [XmlElement(Namespace = "al:1.0.0")]    //note i dont assign value for Element name because it has to be decided by sub classes 
        public string NumberIdentificator{ get; set; }
    }

和子类:

    [Serializable]
    public class DistributionRecieverA : DistributionReceiver
    {
        [XmlElement(Namespace = "al:1.0.0", ElementName = "ANumberIdentificator")]
        public new string ANumberIdentificator { get; set; }
    }

和另一个

    [Serializable]
    public class DistributionRecieverB : DistributionReceiver
    {
        [XmlElement(Namespace = "al:1.0.0", ElementName = "BNumberIdentificator")]
        public new string BNumberIdentificator { get; set; }
    }

问题是：我没有序列化 ANumberIdentificator 和 BNumberIdentificator。

Answer 1

XmlArrayItem 必须枚举数组中所有可能的类型

  XmlArrayItem(ElementName="DistributionReceiver", Type=typeof(DistributionReciever)),   
  XmlArrayItem(ElementName="DistributionRecieverA", Type=typeof(DistributionRecieverA)), 
  XmlArrayItem(ElementName="DistributionRecieverB", Type=typeof(DistributionRecieverB)),

序列化程序需要结束，从 ElementName 到 Runtime-Type。（自己添加您的命名空间）。 XmlArrayItem 的位置是正确的，但是添加了多个 !

如果您的 base-class 是抽象的，请不要为其创建 XmlArrayItem。

Answer 2

看起来 ANumberIdentificator 和 BNumberIdentificator

的模型不正确

我已经使用 xmltocsharp 转换示例 XML 模型看起来像

    [XmlRoot(ElementName = "Receiver", Namespace = "al:2.0.0")]
public class Receiver
{
    [XmlElement(ElementName = "ANumberIdentificator", Namespace = "al:1.0.0")]
    public List<string> ANumberIdentificator { get; set; }
    [XmlElement(ElementName = "BNumberIdentificator", Namespace = "al:1.0.0")]
    public List<string> BNumberIdentificator { get; set; }
}

[XmlRoot(ElementName = "DispatchReceiverGroup", Namespace = "al:1.0.0")]
public class DispatchReceiverGroup
{
    [XmlElement(ElementName = "Receiver", Namespace = "al:2.0.0")]
    public Receiver Receiver { get; set; }
}

[XmlRoot(ElementName = "Dispatch", Namespace = "al:2.0.0")]
public class Dispatch
{
    [XmlElement(ElementName = "MsgIdentificator", Namespace = "al:2.0.0")]
    public string MsgIdentificator { get; set; }
    [XmlElement(ElementName = "DispatchReceiverGroup", Namespace = "al:1.0.0")]
    public DispatchReceiverGroup DispatchReceiverGroup { get; set; }
    [XmlAttribute(AttributeName = "al1", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string Al1 { get; set; }
    [XmlAttribute(AttributeName = "al2", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string Al2 { get; set; }
}

我已经使用 XmlSerializer 将 XML 转换为对象

XmlSerializer serializer = new XmlSerializer(typeof(Dispatch));
        using (TextReader reader = new StringReader(xmlstring))
        {
            //convert the xml to object
            Dispatch result = (Dispatch)serializer.Deserialize(reader);
        }

并且我能够在 Receiver 下读取 A 和 B

Console.WriteLine(result.DispatchReceiverGroup.Receiver.ANumberIdentificator);

Console.WriteLine(result.DispatchReceiverGroup.Receiver.BNumberIdentificator);

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