如何在 .net WebAPI 中验证只有 3 个可能值的字符串值？

Question

我知道这个问题看起来很简单，但我想知道是否有比做更好的方法

if (partner.Type =="value" 或 value2 或 value3)

也许有数据注释？

这是我的实体 POCO

 /// <summary>
    /// Partner Entity
    /// </summary>
    [SharedCosmosCollection("shared")]
    public class Partner : ISharedCosmosEntity
    {
        /// <summary>
        /// Partner id
        /// </summary>
        [JsonProperty("Id")]
        public string Id { get; set; }

        /// <summary>
        /// Partner name
        /// </summary>
        public string PartnerName { get; set; }

        /// <summary>
        /// Partner contact name
        /// </summary>
        public string PartnerContact { get; set; }

        /// <summary>
        /// Partner contact phone
        /// </summary>
        public string PartnerPhone { get; set; }

        /// <summary>
        /// Partner contact Office 365 domain
        /// </summary>
        public string PartnerDomain { get; set; }

        /// <summary>
        /// Partner type, silver, gold or platinum
        /// </summary>
        public string PartnerType { get; set; }

        /// <summary>
        /// Partner start date
        /// </summary>
        public DateTime StartDate { get; set; }

        /// <summary>
        /// Partner end date
        /// </summary>
        public DateTime EndDate { get; set; }

        /// <summary>
        /// Parter enabled
        /// </summary>
        public bool  Enabled { get; set; }

        [CosmosPartitionKey]
        public string CosmosEntityName { get; set; }
    }

这是我的控制器

 [HttpPost]
        public async Task<IHttpActionResult> AddPartner([FromBody]Partner partner)
        {
            var telemetry = new TelemetryClient();
            try
            {
                var partnerStore = CosmosStoreHolder.Instance.CosmosStorePartner;
                if (!ModelState.IsValid)
                {
                    return BadRequest(ModelState);
                }

                var added = await partnerStore.AddAsync(partner);
                return Ok(added);
            }
            catch (Exception ex)
            {
                string guid = Guid.NewGuid().ToString();
                var dt = new Dictionary<string, string>
                {
                    { "Error Lulo: ", guid }
                };

                telemetry.TrackException(ex, dt);
                return BadRequest("Error Lulo: " + guid);
            }
        }

Answer 1

使用正则表达式验证器作为 属性 上的数据注释。

[RegularExpression("^silver$|^gold$|^platinum$", ErrorMessage = "Invalid Value")]
public string PartnerType { get; set; }

P.S。正则表达式可能需要调整，因为我只是在脑海中输入它以匹配您提到的可能值。