创建一个没有后退按钮的 NavigationLink SwiftUI
Create a NavigationLink without back button SwiftUI
我正在尝试 link SomeView1() 中的按钮操作导航到 someView2(),而无需在屏幕顶部设置后退按钮。相反,我想在 SomeView2() 中添加另一个按钮,它将导航回 SomeView1()。这在 SwiftUI 中可行吗?
SomeView1()
struct SomeView1: View {
var body: some View {
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView2()) {
Text("go to SomeView2")
}
Spacer()
}
}
}
}
SomeView2()
struct SomeView2: View {
var body: some View {
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}
}
}
这是它的样子:
您可以在 SomeView2()
中执行类似的操作:
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}.navigationBarBackButtonHidden(true)
我认为您应该在整个导航过程中只使用一个 NavigationView。现在您在彼此内部拥有三个 NavigationView,这会产生三个后退按钮。
所以在你的情况下它会变成这样:
struct SomeView1InsideNavigationView: View { // This should be the first view you present
var body: some View {
NavigationView { // Use NavigationView only once
SomeView1()
}
}
}
struct SomeView1: View {
var body: some View {
VStack { // Do *not* use NavigationView here
//...view's content
NavigationLink(destination: SomeView2()) {
Text("go to SomeView2")
}
Spacer()
}
}
}
struct SomeView2: View {
var body: some View {
VStack { // Do *not* use NavigationView here
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}
}
在这里得到你想要的东西的正确方法是使用presentationMode
环境变量:
import SwiftUI
struct View2: View {
@Environment(\.presentationMode) var presentationMode: Binding<PresentationMode>
var body: some View {
VStack {
Button(action: {
self.presentationMode.wrappedValue.dismiss()
}) {
Text("POP")
}
}
.navigationBarTitle("")
.navigationBarBackButtonHidden(true)
.navigationBarHidden(true)
}
}
struct ContentView: View {
var body: some View {
NavigationView {
NavigationLink(destination: View2()) {
Text("PUSH")
.navigationBarTitle("")
.navigationBarHidden(true)
}
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
我正在尝试 link SomeView1() 中的按钮操作导航到 someView2(),而无需在屏幕顶部设置后退按钮。相反,我想在 SomeView2() 中添加另一个按钮,它将导航回 SomeView1()。这在 SwiftUI 中可行吗?
SomeView1()
struct SomeView1: View {
var body: some View {
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView2()) {
Text("go to SomeView2")
}
Spacer()
}
}
}
}
SomeView2()
struct SomeView2: View {
var body: some View {
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}
}
}
这是它的样子:
您可以在 SomeView2()
中执行类似的操作:
NavigationView {
VStack {
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}.navigationBarBackButtonHidden(true)
我认为您应该在整个导航过程中只使用一个 NavigationView。现在您在彼此内部拥有三个 NavigationView,这会产生三个后退按钮。
所以在你的情况下它会变成这样:
struct SomeView1InsideNavigationView: View { // This should be the first view you present
var body: some View {
NavigationView { // Use NavigationView only once
SomeView1()
}
}
}
struct SomeView1: View {
var body: some View {
VStack { // Do *not* use NavigationView here
//...view's content
NavigationLink(destination: SomeView2()) {
Text("go to SomeView2")
}
Spacer()
}
}
}
struct SomeView2: View {
var body: some View {
VStack { // Do *not* use NavigationView here
//...view's content
NavigationLink(destination: SomeView1()) {
Text("go to SomeView1")
}
Spacer()
}
}
}
在这里得到你想要的东西的正确方法是使用presentationMode
环境变量:
import SwiftUI
struct View2: View {
@Environment(\.presentationMode) var presentationMode: Binding<PresentationMode>
var body: some View {
VStack {
Button(action: {
self.presentationMode.wrappedValue.dismiss()
}) {
Text("POP")
}
}
.navigationBarTitle("")
.navigationBarBackButtonHidden(true)
.navigationBarHidden(true)
}
}
struct ContentView: View {
var body: some View {
NavigationView {
NavigationLink(destination: View2()) {
Text("PUSH")
.navigationBarTitle("")
.navigationBarHidden(true)
}
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}