字典中的函数按值传递

Question

我正在尝试编写一个程序来检查字典中的操作并调用匹配 'key' 的函数。

此程序将根据 'key' 的内容解析该行。

我的问题是，如何将字符串传递给字典调用的函数，以便函数可以解析它，因为字符串并不总是相同，字符串的解析方式也不同。

def format1(opline):                                    # r-type: rd, rs, rt
    opline = opline.split('', 1)[1]                     # removes instruction
    rd, rs, rt = opline.split()                         # splits into 3 registers
    return rd, rs, rt                                   # returns all registers

inst_match = {'add' : format1}                          # dictionary (more.       
                                                        # key/funct pairs
                                                        # will be added

instruction_storage = 'add 9 0 255'

instructions = instruction_storage.split()[0]       # get key from string

inst_match[instructions](instruction_storage)       # passes key to search and string to pass into function

^ 上面的代码只是一个测试。我最终将从多行文件中读取 "instruction_storage"。

Answer 1

我不太清楚你到底在找什么，但我猜一下：

def format1(opline, string):
    print('format1({!r}, {!r})'.format(opline, string))
    opline = opline.split(' ', 1)[1]
    rd, rs, rt = opline.split()
    return rd, rs, rt

def format2(opline, string):
    print('format2({!r}, {!r})'.format(opline, string))
    opline = opline.split(' ', 1)[1]
    rd, rs, rt = opline.split()
    return rd, rs, rt

inst_match = {'add': format1,
              'sub': format2}

instruction_storage = [('add 9 0 255', 'string1'),
                       ('sub 10 1 127', 'string2')]

for instruction in instruction_storage:
    opline, string = instruction
    opcode = opline.split()[0]

    try:
        inst_match[opcode](opline, string)
    except KeyError:
        print('unknown instruction: {!r}'.format(opcode))

输出：

format1('add 9 0 255', 'string1')
format2('sub 10 1 127', 'string2')

字典中的函数按值传递

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