LATCH Primitive 禁用输出？

Question

所以我理解锁存器的概念，但我没有看到我是如何在这里推断锁存器的，因为我的 else 条件应该涵盖通过这个过程的所有可能路径。 Quartus 告诉我它正在禁用 greenLEDS 和 redLED，因为 LATCH 原语，以及它们上有一个推断的锁存器。我在这里遗漏了什么吗？

process(current,advance,playerWins,dealerWins) begin
  if(advance) then
        case current is
          when START =>
                deal           <= '1';
                dealTo         <= '1';
                dealToCardSlot <= "00";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when PT1 =>
                deal           <= '1';
                dealTo         <= '1';
                dealToCardSlot <= "01";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when DT1 =>
                deal           <= '1';
                dealTo         <= '0';
                dealToCardSlot <= "00";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when PT2 =>
                deal           <= '1';
                dealTo         <= '1';
                dealToCardSlot <= "10";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when PT3 =>
                deal           <= '1';
                dealTo         <= '1';
                dealToCardSlot <= "11";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when DT2 =>
                deal           <= '1';
                dealTo         <= '0';
                dealToCardSlot <= "01";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when DT3 =>
                deal           <= '1';
                dealTo         <= '0';
                dealToCardSlot <= "10";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when DT4 =>
                deal           <= '1';
                dealTo         <= '0';
                dealToCardSlot <= "11";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when WIN =>
                deal           <= '0';
                dealTo         <= '0';
                dealToCardSlot <= "00";
                if(playerWins) then
                    greenLeds <= (others => '1');
                elsif(dealerWins) then
                    redLeds <= (others => '1');
                else
                    greenLeds <= (others => '0');
                    redLeds <= (others => '0');
                end if;
          when ENDGAME =>
                deal           <= '0';
                dealTo         <= '1';
                dealToCardSlot <= "00";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          when others =>
                deal           <= '0';
                dealTo         <= '0';
                dealToCardSlot <= "00";
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
          end case;
  else
    deal           <= '0';
    dealTo         <= '0';
    dealToCardSlot <= "00";
    greenLeds <= (others => '0');
    redLeds <= (others => '0');
  end if;
end process;

Answer 1

      when WIN =>
            deal           <= '0';
            dealTo         <= '0';
            dealToCardSlot <= "00";
            if(playerWins) then
                greenLeds <= (others => '1');
            elsif(dealerWins) then
                redLeds <= (others => '1');
            else
                greenLeds <= (others => '0');
                redLeds <= (others => '0');
            end if;

如果 playerWins 为假且 dealerWins 为真，则不分配 redLeds。同样，如果 playerWins 为真，则不分配 greenLeds。

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