如何将一行转换为列表并读取其元素：Python

Question

我正在读取一个如下所示的文件： Ikard Wynne Llp|[('209.163.183.92', '209.163.183.95')]

    Innovation Technologies Ltd|[('91.238.88.0', '91.238.91.255'), ('195.128.153.0', '195.128.153.255')]
    House Of Flowers|[('69.15.170.220', '69.15.170.223'), ('108.178.223.20', '108.178.223.23')]
    Hertitage Peak Charter School|[('66.81.93.192', '66.81.93.207')]

我愿意转换'|'后面的部分到列表，然后从列表中读取元组。我正在使用这个脚本来做到这一点，但我的脚本将每个列表识别为一个元素而不是每个元组。有没有人知道如何解决这个问题？

for line in g:
    org= line.split("|")[0]
    ranges = [line.split('|')[1]]
    for range in ranges:
    print (range)

输出：

[('91.238.88.0', '91.238.91.255'), ('195.128.153.0', '195.128.153.255')]
[('69.15.170.220', '69.15.170.223'), ('108.178.223.20', '108.178.223.23')]
[('66.81.93.192', '66.81.93.207')]

        for ip in range:
        print (ip)

输出：

[
(
'
9
1
.
1
9
5
.
1
7
2
.
0
'
,

Answer 1

使用 ast 模块中的 literal_eval：

>>> import ast
>>> s = "Innovation Technologies Ltd|[('91.238.88.0', '91.238.91.255'), ('195.128.153.0', '195.128.153.255')]"
>>> z = ast.literal_eval(s.split('|')[1])
>>> z
[('91.238.88.0', '91.238.91.255'), ('195.128.153.0', '195.128.153.255')]
>>> z[0]
('91.238.88.0', '91.238.91.255')
>>> z[0][1]
'91.238.91.255'
>>> type(z)
<type 'list'>
>>> type(z[0])
<type 'tuple'>

来自文档：

Safely evaluate an expression node or a Unicode or Latin-1 encoded string containing a Python literal or container display. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.

This can be used for safely evaluating strings containing Python values from untrusted sources without the need to parse the values oneself. It is not capable of evaluating arbitrarily complex expressions, for example involving operators or indexing.

如何将一行转换为列表并读取其元素：Python

How to convert a line to a list and read its elements: Python

python

list

elements