LP / MILP (CPLEX) 困难
LP / MILP (CPLEX) difficulties
我正在尝试使用 CPLEX 解决优化问题。
//Variables
int n = ...;
range time =1..n; //n definido em data
dvar float+ c[time] in 0..0.9;
dvar float+ d[time] in 0..0.9;
dvar float+ x[time];
int beta[time]=...;
float pc[time]=...;
float pd[time]=...;
//Expressions
dexpr float objective = sum(t in time) (d[t]*pd[t]-c[t]*pc[t]);
//Model
maximize objective;
subject to {
x[1] == 0.5;
c[1] == 0;
d[1] == 0;
forall(t in time)
const1:
x[t] <= 1;
forall(t in time: t!=1)
const2:
(x[t] == x[t-1] + c[t] - beta[t]*d[t]);
}
谁能告诉我如何防止 d[t] 和 c[t] 同时大于 0?
基本上我想这样写:
if( d[t] > 0) c[t] = 0;
谢谢,
您可以使用逻辑约束:
( d[t] <= 0) || (c[t] <= 0);
我正在尝试使用 CPLEX 解决优化问题。
//Variables
int n = ...;
range time =1..n; //n definido em data
dvar float+ c[time] in 0..0.9;
dvar float+ d[time] in 0..0.9;
dvar float+ x[time];
int beta[time]=...;
float pc[time]=...;
float pd[time]=...;
//Expressions
dexpr float objective = sum(t in time) (d[t]*pd[t]-c[t]*pc[t]);
//Model
maximize objective;
subject to {
x[1] == 0.5;
c[1] == 0;
d[1] == 0;
forall(t in time)
const1:
x[t] <= 1;
forall(t in time: t!=1)
const2:
(x[t] == x[t-1] + c[t] - beta[t]*d[t]);
}
谁能告诉我如何防止 d[t] 和 c[t] 同时大于 0?
基本上我想这样写:
if( d[t] > 0) c[t] = 0;
谢谢,
您可以使用逻辑约束:
( d[t] <= 0) || (c[t] <= 0);