如何从 Lua 事件处理函数中获取 'self'？

Question

local tbl = {a = 1}

-- Passed and executed function
function tbl:handleFunc(x, y)
    print(self.a + x + y)
end

-- I know the above code is syntax sugar.
-- tbl["handleFunc"] = function(self, x, y)
--     print(self.a + x + y)
-- end

-- Register event handlers that I can't control the call
Frame:SetScript("OnClick", tbl.handleFunc)

-- Probably called when an event occurs.
tbl.handleFunc(2, 3)

-- Then it will be like this.
tbl.handleFunc(2, 3, nil)

-- So I wrote a function like this
function tbl.handleFunc(x, y)
    local self = tbl  -- This variable is too cumbersome
    -- And this way, every time I call a function, I need to check whether the function definition is a dot (.) Or colon (:)

end

调用函数时，在无法通过self的情况下，有没有办法使用self？

如果没有，我该如何设计？

[已解决]我用了翻译器，但我想礼貌一点。谢谢你的好回答。

Answer 1

只需使用调用实际函数的匿名函数

Frame:SetScript("OnClick", function(x,y) tbl:handleFunc(x, y) end)

Answer 2

避免不必要工作的一种方法是编写一个函数，在您将其注册为处理程序之前为您包装该函数：

local tbl = {a = 1}

function tbl:handleFunc(x, y)
    print(self.a + x + y)
end

function wrap_with(obj, func)
    return function(...)
        return func(obj, ...)
    end
end

Frame:SetScript("OnClick", wrap_with(tbl, tbl.handleFunc))

如何从 Lua 事件处理函数中获取 'self'？

How to get 'self' from Lua event handler function?

lua

add-on

world-of-warcraft