Xpath: 第一个 letter/string 紧跟在元素之后

Question

我有以下XML种可能性：

<metamark/><anything>. <anything2>bla</anything2>.</anything>
<metamark/>.<anything> <anything2>bla</anything2>.</anything>
<metamark/><anything><anything2>bla</anything2>.</anything>

我想得到第一个“.”所以我尝试了：

starts-with(metamark[not(descendant::text())]/following-sibling::text()[1],'.')

上面第 2 行工作正常，但我错过了第 1 行。所以我做到了：

starts-with(metamark[not(descendant::text())]/following-sibling::text()[1],'.') or starts-with(metamark[not(descendant::text())]/following-sibling::*[1]/text()[1],'.')

现在适用于上面的所有行。但是第 3 行不应该是真的，因为我只想要“。”要么紧跟在空 <metamark/> 之后，要么紧跟在紧随其后的兄弟的第一个字符串之后，但如果在“.”

之前该兄弟的任何后代元素中有文本，则不会

简而言之：第一个文本（最接近元素后的实际结束“>”。我将如何实现？

Answer 1

怎么样："The first text node that follows any <metamark> as long as it starts with '.'"

//metamark[not(descendant::text())]/following::text()[1][starts-with(., '.')]

在

<r>
  <metamark/><anything>. yes1<anything2>bla</anything2>. no1</anything>
  <metamark/>. yes2<anything> <anything2>bla</anything2>. no2</anything>
  <metamark/><anything><anything2>bla</anything2>. no3</anything>
</r>

此检索

'. yes1'
'. yes2'

following::轴忽略嵌套，这对这个任务很有用。

Xpath: 第一个 letter/string 紧跟在元素之后

Xpath: First letter/string immediately following element

xml

string

xpath

xpath-2.0