Azure DevOps Odata Group by child 属性 不工作

Question

我正在使用 Azure DevOps Odata 端点从我的项目中检索数据。

现在我面临无法根据工作项的子 属性 按结果分组的问题。 以下 ODATA 查询 returns 给我一个错误信息：

https://analytics.dev.azure.com/<organisation>/<project>/_odata/v2.0/WorkItems?
$filter=WorkItemType eq 'Activity'&
$select=AssignedTo/UserName,TotalCount&
$apply=groupby((AssignedTo/UserName, WorkItemType),aggregate($count as TotalCount))&
$expand=AssignedTo($select=UserName)

VS403483: The query specified in the URI is not valid: VS403522: The property 'AssignedTo' is not available on the specified Project(s). Please remove 'AssignedTo' from your query and try again..","innererror":{"message":"VS403522: The property 'AssignedTo' is not available on the specified Project(s). Please remove 'AssignedTo' from your query and try again.

{
    "State": "Closed",
    "AssignedTo": {
        "UserName": "User 2"
    }
},
{
    "State": "New",
    "AssignedTo": {
        "UserName": "User 1"
    }
}

当我尝试对普通 属性 执行相同操作时，一切正常：

https://analytics.dev.azure.com/<organisation>/<project>/_odata/v2.0/WorkItems?
$filter=WorkItemType eq 'Activity'&
$select=State,TotalCount&
$apply=groupby((State, WorkItemType),aggregate($count as TotalCount))

Answer 1

您可以使用以下查询 url。

https://analytics.dev.azure.com/{orgname}/{projectname}/_odata/v2.0/WorkItems?
$apply=filter(WorkItemType eq 'Bug')/groupby((AssignedTo/UserName, WorkItemType),aggregate($count as TotalCount))
&select=AssignedTo/UserName,TotalCount

然后你会得到如下结果。

{
    "@odata.context": "https://analytics.dev.azure.com/{orgname}/{projectname}/_odata/v2.0/$metadata#WorkItems(AssignedTo(UserName),WorkItemType,TotalCount)",
    "value": [
        {
            "@odata.id": null,
            "WorkItemType": "Bug",
            "TotalCount": 3,
            "AssignedTo": {
                "@odata.id": null,
                "UserName": "{username1}"
            }
        },
        {
            "@odata.id": null,
            "WorkItemType": "Bug",
            "TotalCount": 4,
            "AssignedTo": {
                "@odata.id": null,
                "UserName": "{username2}"
            }
        }
    ]
}

希望对您有所帮助。