使用查找比较数据并使用 python 仅输出数据中最长的短语？

Question

我有一个 csv，其中包含 "KKR" 到 "MBI" 数据的映射。我想从用户给定的数据中执行查找，以从 KKR 中提取最长的匹配短语（如果包含长短语的单词，则忽略小短语）

#os.chdir("kkr_lookup")
data = pd.read_csv("KKR_MBI_MAP.csv")

dfData = pd.DataFrame(data)

dfVerbatim = pd.DataFrame()

dataVerbatim = {'verbatim': ['She experienced skin allergy and hair loss after using it for 2-3 weeks']}
dfVerbatim = pd.DataFrame(dataVerbatim, columns = ['verbatim'])


for index, frame in dfData.iterrows():
    if pd.notnull(frame['KKR']) & dfVerbatim['verbatim'].str.contains(frame['KKR'], case=False).bool() :
        k=(frame['MBI']).lower()
        l=(frame['KKR']).lower()
        print("MBI:",l)
        #print("MBI:",k)

代码给出的输出为：

allergy
hair loss
skin allergy

但我需要：

skin allergy
hair loss

这里我已经编码以从用户输入数据中提取术语。但它提取了 "allergy" 和 "skin allergy" 而我在这里只需要 "skin allergy" 。请帮助我...

Answer 1

import re

list_of_strings=["skin allergy","hair loss","allergy","hair", "skin"]
sentence="She experienced skin allergy and hair loss after using it for 2-3 weeks"
pattern = re.compile(r"(\b" + "|".join(list_of_strings) + r")\b")

m = pattern.findall(sentence)
print(m)

使用查找比较数据并使用 python 仅输出数据中最长的短语？

Comparing data using lookup and output only longest phrase in the data using python?

python

lookup

pattern-matching

string-matching