如何将单击的 ListView 项目的文本发送到我的新 activity?
How do I send the text of the ListView item that was clicked to my new activity?
我希望有人单击我的 ListView 中的一个项目,然后我的新 activity 将开始,他们单击的项目的文本应设置为我的新 activity。目前使用以下代码,我的 TextView 结果是:
'com.example.draft.AnimalNames@31571cf'
这是我在 MainActivity.java 中的内容:
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String clickedName = (list.getItemAtPosition(position).toString());
Intent intent = new Intent(MainActivity.this, Profile.class);
intent.putExtra("clickedName", clickedName);
startActivity(intent);
System.out.println(clickedName);
}
});
在我的新 activity 中:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.profile_layout);
Intent intent = getIntent();
String clickedName = intent.getStringExtra("clickedName");
animalName = findViewById(R.id.textView);
animalName.setText(clickedName);
}
在我的 AnimalNames.java 文件中:
public class AnimalNames {
private String animalName;
public AnimalNames(String animalName) {
this.animalName = animalName;
}
public String getanimalName() {
return this.animalName;
}
}
我认为这与我的问题无关,但这是我的 ListViewAdapter.java 文件:
public class ListViewAdapter extends BaseAdapter {
// Declare Variables
Context mContext;
LayoutInflater inflater;
private List<AnimalNames> animalNamesList; // Declare a null variable
private ArrayList<AnimalNames> arraylist; // Declare a null array
public ListViewAdapter(Context context, List<AnimalNames> animalNamesList) {
mContext = context;
this.animalNamesList = animalNamesList;
inflater = LayoutInflater.from(mContext);
this.arraylist = new ArrayList<AnimalNames>();
this.arraylist.addAll(animalNamesList);
}
public class ViewHolder {
TextView name;
}
@Override
public int getCount() {
return animalNamesList.size();
}
@Override
public AnimalNames getItem(int position) {
return animalNamesList.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
public View getView(final int position, View view, ViewGroup parent) {
final ViewHolder holder;
if (view == null) {
holder = new ViewHolder();
view = inflater.inflate(R.layout.list_view_items, null); // Locate the TextViews in list_view_items.xml
holder.name = (TextView) view.findViewById(R.id.name);
view.setTag(holder);
} else {
holder = (ViewHolder) view.getTag();
}
// Set the results into TextViews
holder.name.setText(animalNamesList.get(position).getanimalName());
return view;
}
// Filter Class
public void filter(String charText) {
charText = charText.toLowerCase(Locale.getDefault());
animalNamesList.clear();
if (charText.length() == 0) {
animalNamesList.addAll(arraylist);
} else {
for (AnimalNames wp : arraylist) {
if (wp.getanimalName().toLowerCase(Locale.getDefault()).contains(charText)) {
animalNamesList.add(wp);
}
}
}
notifyDataSetChanged();
}
}
String clickedName = (list.getItemAtPosition(position).toString());
通过调用toString()
方法,它会给你对象引用,这就是你在TextView中得到的。
根据您的代码,如果您希望看到动物名称,您应该这样做(并将方法名称固定为 getAnimalName):
String clickedName = ((AnimalNames)list.getItemAtPosition(position)).getanimalName();
getItemAtPosition()
returns 一个对象,所以你需要将它转换为正确的 class.
我希望有人单击我的 ListView 中的一个项目,然后我的新 activity 将开始,他们单击的项目的文本应设置为我的新 activity。目前使用以下代码,我的 TextView 结果是: 'com.example.draft.AnimalNames@31571cf'
这是我在 MainActivity.java 中的内容:
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String clickedName = (list.getItemAtPosition(position).toString());
Intent intent = new Intent(MainActivity.this, Profile.class);
intent.putExtra("clickedName", clickedName);
startActivity(intent);
System.out.println(clickedName);
}
});
在我的新 activity 中:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.profile_layout);
Intent intent = getIntent();
String clickedName = intent.getStringExtra("clickedName");
animalName = findViewById(R.id.textView);
animalName.setText(clickedName);
}
在我的 AnimalNames.java 文件中:
public class AnimalNames {
private String animalName;
public AnimalNames(String animalName) {
this.animalName = animalName;
}
public String getanimalName() {
return this.animalName;
}
}
我认为这与我的问题无关,但这是我的 ListViewAdapter.java 文件:
public class ListViewAdapter extends BaseAdapter {
// Declare Variables
Context mContext;
LayoutInflater inflater;
private List<AnimalNames> animalNamesList; // Declare a null variable
private ArrayList<AnimalNames> arraylist; // Declare a null array
public ListViewAdapter(Context context, List<AnimalNames> animalNamesList) {
mContext = context;
this.animalNamesList = animalNamesList;
inflater = LayoutInflater.from(mContext);
this.arraylist = new ArrayList<AnimalNames>();
this.arraylist.addAll(animalNamesList);
}
public class ViewHolder {
TextView name;
}
@Override
public int getCount() {
return animalNamesList.size();
}
@Override
public AnimalNames getItem(int position) {
return animalNamesList.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
public View getView(final int position, View view, ViewGroup parent) {
final ViewHolder holder;
if (view == null) {
holder = new ViewHolder();
view = inflater.inflate(R.layout.list_view_items, null); // Locate the TextViews in list_view_items.xml
holder.name = (TextView) view.findViewById(R.id.name);
view.setTag(holder);
} else {
holder = (ViewHolder) view.getTag();
}
// Set the results into TextViews
holder.name.setText(animalNamesList.get(position).getanimalName());
return view;
}
// Filter Class
public void filter(String charText) {
charText = charText.toLowerCase(Locale.getDefault());
animalNamesList.clear();
if (charText.length() == 0) {
animalNamesList.addAll(arraylist);
} else {
for (AnimalNames wp : arraylist) {
if (wp.getanimalName().toLowerCase(Locale.getDefault()).contains(charText)) {
animalNamesList.add(wp);
}
}
}
notifyDataSetChanged();
}
}
String clickedName = (list.getItemAtPosition(position).toString());
通过调用toString()
方法,它会给你对象引用,这就是你在TextView中得到的。
根据您的代码,如果您希望看到动物名称,您应该这样做(并将方法名称固定为 getAnimalName):
String clickedName = ((AnimalNames)list.getItemAtPosition(position)).getanimalName();
getItemAtPosition()
returns 一个对象,所以你需要将它转换为正确的 class.