复制文件时嵌套try catch

Question

我正在从不包含文件扩展名的 .csv 文件位置复制文件。我试图对有效的“.tif”进行硬编码，但还有其他文件类型被遗漏了。我试图使用下面的，但它抛出一个错误，指出路径显示为 C:\users...

    if (-not (Test-Path -Path $path -PathType Container)) {
        New-Item -Path $path -ItemType Directory >$null
    }
    #Perform Copy
    echo "Copying document and Prepending Document Date"

    try {
        $copy = [IO.FileInfo]$_.'Document File Path'+'.tif'
        $copy | Copy-Item -Destination "$path$($_.'Document Date')_$($copy.Name)"
    } catch {
        try {
              $copy = [IO.FileInfo]$_.'Document File Path'+'.pdf'
              $copy | Copy-Item -Destination "$path$($_.'Document Date')_$($copy.Name)"
        } catch {
            $copy = [IO.FileInfo]$_.'Document File Path'+'.jpg'
            $copy | Copy-Item -Destination "$path$($_.'Document Date')_$($copy.Name)"
        } finally {
            $copy = [IO.FileInfo]$_.'Document File Path'+'.doc'
            $copy | Copy-Item -Destination "$path$($_.'Document Date')_$($copy.Name)"
        }
    } finally {
        $copy = [IO.FileInfo]$_.'Document File Path'+'.docx'
        $copy | Copy-Item -Destination "$path$($_.'Document Date')_$($copy.Name)"
    }
}

Answer 1

如果您一次只有一个匹配文件，这样的方法应该有效：

$name = Split-Path -Leaf $_.'Document File Path'
$src  = $_.'Document File Path'
$dst  = Join-Path $path ('{0}_{1}' -f $_.'Document Date', $name)
Get-ChildItem "${src}.*" | Copy-Item -Destination { $dst + $_.Extension }

如果这会偶然匹配您不想复制的其他文件（例如 $name 是 "foo" 并且您想复制 "foo.tif" 而不是 "foo.bar.txt" ) 您可以在复制前按基本名称过滤：

Get-ChildItem "${src}.*" | Where-Object {
    $_.BaseName -eq $name
} | Copy-Item -Destination { $dst + $_.Extension }

复制文件时嵌套try catch

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