如何避免在 Python 中链接 3d 数组？

Question

我一直在尝试复制 3D 阵列，但似乎无论我做什么都无济于事；修改副本，也修改原件

我已经尝试了 this 问题中给出的最重要建议的多个版本。

任何人都可以向我解释为什么这段代码在复制后会修改 Clients 数组，以及如何避免这种情况？

##### This block is to get and save the information

import csv

import datetime

import glob
import os

#import copy

from datetime import timedelta

list_of_files = glob.glob(r'U:\UEL\Sales and Marketing\Relationship - Sales\Team\Edinburgh Clients\Portal backups\Full export archive\*.csv') # * means all if need specific format then *.csv
latest_file = max(list_of_files, key=os.path.getctime)

with open(latest_file, newline='') as csvfile:
    data = list(csv.reader(csvfile))
    Vheaders = data[0]
    data.pop(0)

Clients = list(set(list(zip(*data))[9]))

i = 0
for line in Clients:
    Clients[i] = [Clients[i]]
    i = i + 1

Voids = []
CoTs = []

for row in Clients:
    Voids.append(row)

for row in Clients:
    CoTs.append(row)

#Voids = list(Clients) #This creates an array of arrays, an array of voids for each client

#CoTs = list(Voids) #Same as above for CoTs

#import pdb
#pdb.set_trace()


i = 0

for row in Clients:
    for line in data:
        #if line[0] == '443179':
            #import pdb
            #pdb.set_trace()
        if (datetime.date.today() - timedelta(days=7)) <= datetime.datetime.strptime(line[2], "%d/%m/%Y").date() < datetime.date.today(): 
            if line[9] == row[0]:
                Voids[i].append(line)
            else:
                pass
        else:
            pass
    i = i + 1

Answer 1

您需要 deepcopy。 "Assignment statements in Python do not copy objects, they create bindings between a target and an object. For collections that are mutable or contain mutable items, a copy is sometimes needed so one can change one copy without changing the other."

如何避免在 Python 中链接 3d 数组？

How do you avoid 3d arrays from being linked in Python?

python

copy

list

deep-copy