String 类型的属性与以下类型不匹配：架构中的对象 JSON 架构验证器

Question

我正在尝试为我的 JSON 对象编写一个 JSON 架构，但我无法跟踪错误。我希望我的 JSON 对象以下列方式存储在 Java 中：

public class Category {
   private Map<String, List<String>> categoryMapping;
}

样本JSON：

{
  "categoryMapping": {
    "categoryA": ["a","b","c"],
    "categoryB": ["x","y","z"],
    "categoryC": ["x","y","z"]
  }
}

但是，如果我按以下方式编写架构：

{
  "$schema": "http://json-schema.org/draft-04/schema#",
  "type": "object",
  "title": "$id$",
  "description": "list_of_values-1",
  "required": [
    "categoryMapping"
  ],
  "properties": {
    "categoryMapping": {
      "$id": "#/properties/categoryMapping",
      "type": "object",
      "title": "The categoryMapping Schema",
      "properties": {
          "type": "array",
          "items": {
            "type": "string"
          }
        }
    }
  }
}

我收到以下错误：字符串类型的属性“#/properties/categoryMapping/properties/type”与以下类型不匹配：架构中的对象 http://json-schema.org/draft-04/schema#

但如果我指定类别的类型，它会起作用：

"$schema": "http://json-schema.org/draft-04/schema#",
"type": "object",
"title": "$id$",
"description": "list_of_values-1",
"properties": {
    "categoryMapping": {
      "$id": "#/properties/categoryMapping",
      "type": "object",
      "title": "The Categorymapping Schema",
      "required": [
        "categoryA",
        "categoryB",
        "categoryC"
      ],
      "properties": {
        "categoryA": {
          "$id": "#/properties/categoryMapping/properties/categoryA",
          "type": "array",
          "title": "The Categorya Schema",
          "items": {
            "$id": "#/properties/categoryMapping/properties/categoryA/items",
            "type": "string",
            "title": "The Items Schema",
            "default": "",
            "examples": [
              "a",
              "b",
              "c"
            ],
            "pattern": "^(.*)$"
          }
        },
        "categoryB": {
          "$id": "#/properties/categoryMapping/properties/categoryB",
          "type": "array",
          "title": "The Categoryb Schema",
          "items": {
            "$id": "#/properties/categoryMapping/properties/categoryB/items",
            "type": "string",
            "title": "The Items Schema",
            "default": "",
            "examples": [
              "x",
              "y",
              "z"
            ],
            "pattern": "^(.*)$"
          }
        },
        "categoryC": {
          "$id": "#/properties/categoryMapping/properties/categoryC",
          "type": "array",
          "title": "The Categoryc Schema",
          "items": {
            "$id": "#/properties/categoryMapping/properties/categoryC/items",
            "type": "string",
            "title": "The Items Schema",
            "default": "",
            "examples": [
              "x",
              "y",
              "z"
            ],
            "pattern": "^(.*)$"
          }
        }
      }
    }
  }
}

有没有一种方法可以在不显式指定所有类别类型列表的情况下编写模式？

Answer 1

因此您的示例 JSON 实际上是具有三个属性的类型，这就是为什么您生成的模式要求您明确定义每个属性，即使它们实际上属于同一类型.

如果您愿意稍微修改一下样本 json，但是：

{
  "categoryMapping": [
    {
      "name": "categoryA",
      "map": ["a","b","c"]
    },
    {
      "name": "categoryB",
      "map": ["x","y","z"]
    },
    {
      "name": "categoryC",
      "map": ["x","y","z"]
    }
  ]
}

然后您可以使用以下架构对其进行验证：

{
  "$schema": "http://json-schema.org/draft-07/schema#",
  "type": "object",
  "properties": {
    "categoryMapping": {
      "type": "array",
      "items": {
        "type": "object",
        "required": [
          "name",
          "map"
        ],
        "properties": {
          "name": {
            "type": "string"
          },
          "map": {
            "type": "array",
            "items": {
              "type": "string"
            }
          }
        }
      }
    }
  }
}

因为您可以指定数组中允许的最小和最大项目数，所以您可以将类别数限制为 3，如果您愿意，也可以将“地图”数限制为 3。

String 类型的属性与以下类型不匹配：架构中的对象 JSON 架构验证器

The property of type String did not match the following type: object in schema JSON Schema validator

java

json

jsonschema

json-schema-validator

String 类型的 属性 与以下类型不匹配：架构中的对象 JSON 架构验证器

The property of type String did not match the following type: object in schema JSON Schema validator

java

json

jsonschema

json-schema-validator

String 类型的属性与以下类型不匹配：架构中的对象 JSON 架构验证器