能够使用带 python 和 Linux 的 SSH，但不能使用带 python 和 Sonicwall 的 SSH

Question

我正在 python 中使用 Paramiko 来自动执行各种 SSH 任务。我想做的一件事是运行 sonicwall 上的一些命令。我有一些代码可以让我在 Ubuntu VM 上执行运行命令，但相同的代码不适用于 Sonicwall。唯一改变的是变量（用户名、密码、IP 地址等）下面是我收到的代码和错误。任何人都可以帮助启发我为什么这没有按预期工作吗？


ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
host = '192.168.16.75'
port, user, password = 22, 'scott', 'scott'
ssh.connect(host, port,  user, password)
stdin, stdout, stderr = ssh.exec_command("ls -l")

for line in stdout.readlines():
    print(line)

ssh.close()

#ABOVE WORKS W/ UBUNTU

#BELOW DOES NOT WORK WITH SONICWALL

import paramiko

ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
host = '192.168.16.63'
port, user, password = 22, 'admin', 'password'
ssh.connect(host, port,  user, password)
stdin, stdout, stderr = ssh.exec_command("show arp")

for line in stdout.readlines():
    print(line)

#BELOW IS THE ERRORS PYTHON THROWS

C:\Users\scott\AppData\Local\Programs\Python\Python37-32\python.exe C:/Users/scott/.PyCharmCE2019.2/config/scratches/scratch_6.py
Traceback (most recent call last):
  File "C:/Users/scott/.PyCharmCE2019.2/config/scratches/scratch_6.py", line 8, in <module>
    stdin, stdout, stderr = ssh.exec_command("show arp")
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\client.py", line 514, in exec_command
    chan.exec_command(command)
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\channel.py", line 72, in _check
    return func(self, *args, **kwds)
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\channel.py", line 257, in exec_command
    self._wait_for_event()
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\channel.py", line 1226, in _wait_for_event
    raise e
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\transport.py", line 2055, in run
    ptype, m = self.packetizer.read_message()
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\packet.py", line 459, in read_message
    header = self.read_all(self.__block_size_in, check_rekey=True)
  File "C:\Users\scott\AppData\Local\Programs\Python\Python37-32\lib\site-packages\paramiko\packet.py", line 303, in read_all
    raise EOFError()
EOFError

Process finished with exit code 1 ```

Answer 1

您的 SSH 服务器可能不允许 exec_command()。

您可以通过执行以下 ssh 命令来验证这一点：

ssh user@host c i eth i

如果你得到

"Connection to x.x.x. closed by remote host."

则不支持

您应该改为在 paramiko 中启动交互式 shell：

ssh = paramiko.SSHClient()
ssh.connect('credentials here')
chan = ssh.invoke_shell()
chan.send('command here\n')
output = chan.recv()

能够使用带 python 和 Linux 的 SSH，但不能使用带 python 和 Sonicwall 的 SSH

Able to use SSH w/ python and Linux but not able to use SSH w/ python and Sonicwall

python

firewall

paramiko