我可以为 std 命名空间添加推导指南吗?

Can I add a deduction guide to `std` namespace?

假设我想制作一个新的演绎指南,使以下内容成为可能?

std::string str;
std::basic_string_view sv = str;

这样定制好吗?

[namespace.std]/2.4:

The behavior of a C++ program is undefined if it declares [...] a deduction guide for any standard library class template.