如何在层次结构 table 中查找任何内容？

Question

我无法查询层次结构 table:

select *
from user_info
where user = 1;

user level value
1    1     Jackson
1    2     Pollock
1    3     1989-02-03
1    4     male
1    5     single

如果我想获得与用户 1 在级别 1、2、3 和 4 中具有完全相同值的所有用户怎么办？

Answer 1

可能最简单的方法是listagg():

with u as (
      select u.user, listagg(value, '|') within group (order by level) as vals
      from user_info u
      where level between 1 and 4
     )
select
from u join
     u1
     on u.vals = u1.vals and u1.user = 1;

更传统的方法是自连接：

select u.user
from user_info u join
     user_info u1
     on u1.level = u.level and
        u1.value = u.value and
        u1.user = 1
where u1.level between 1 and 4
group by u.user
having count(*) = 4;   -- four levels match

如何在层次结构 table 中查找任何内容？

How to find anything in a level-structured table?

sql

oracle

hierarchical-data