如何读取字符串以获取 GNU Guile 中的用户输入？

Question

我正在尝试制作剪刀石头布游戏来帮助自己学习 GNU Guile。我在获取用户输入（即玩家在游戏中的选择）时遇到了障碍。如果我将它设置为一个字符串，那么游戏就可以正常运行。如果我使用 (read) 我会从查找中返回 #f 作为类型。我尝试格式化 read 以使其成为字符串，但没有用。

(define (print a)
  (display a)
  (newline))

(define choices (make-hash-table 3))
(hashq-set! choices "r" "s")
(hashq-set! choices "s" "p")
(hashq-set! choices "p" "r")

(define (cpu-choice) (list-ref (list "r" "p" "s") (random 3)))

(print "You are playing rock paper scissors.")
(print "Type r for rock, p for paper, and s for scissors.")
(define draw
  ;; "s" ; This works as a test.
 (read (open-input-string (read))) ; Can't get user in as string, so the hashq-ref will work.
  )

(define cpu-draw (cpu-choice))

;; debug
(print (format #f "Player enterd ~a" draw))
(print (format #f "Player needs to with ~a" (hashq-ref choices draw))) ; Keeps coming back as #f
(print (format #f "CPU has entered ~a" cpu-draw))

;; norm
(newline)
(when (eq? draw cpu-draw)
  (print "There was a tie")
  (exit))

(when (eq? (hashq-ref choices draw) cpu-draw)
  (print "You have won.")
  (exit))

(print "You have failed. The computer won.")

如何从用户那里得到一个字符串？可能类似于 (str (read)) 或 (read-string)（读取为字符串）。

$ guile --version
guile (GNU Guile) 2.0.13

更新

我只想提一下，虽然批准的答案是正确的，但我在写这篇文章时不明白 Guile/Scheme 是如何处理字符串和符号的。让程序运行的唯一方法是将 choices 和 cpu-choice 列表中的所有字符串更改为符号。例如：

(hashq-set! choices 'r 's)

(list 'r 'p 's)

谢谢 Óscar López 的帮助。

Answer 1

除非您用双引号将输入括起来，否则您键入的值将被解释为符号。试试这个：

(define str (read))
> "hello"

或者这样：

(define str (symbol->string (read)))
> hello

无论如何，str 现在将保存一个实际的字符串：

str
=> "hello"

如何读取字符串以获取 GNU Guile 中的用户输入？

How to read a string to get user input in GNU Guile?

scheme

command-line-interface

lisp

user-input

guile

更新