SQL 查找前 8 小时内标记的总时数

Question

我的目标是找到一天中每个人的轮班工作总时数或每人轮班的分数，这些小时数被标记为一个值，并且在任何一天的前 8 个小时内工作，不包括休息时间。然后显示标记的班次以及符合条件的总价值。

例子

凌晨 2 点 - 凌晨 4 点（2 小时）- 正常班次
上午 5 点 - 上午 9 点（4 小时）- 标记班次
上午 10 点 - 下午 3 点（5 小时）- 标记班次

符合条件的总计 4 小时（上午 5 点 - 上午 9 点）+ 2 小时（上午 10 点 - 中午 12 点）

来源Table格式

DECLARE @Table TABLE
(
    PersonID INT
    , WorkDate DATETIME
    , StartTime DATETIME
    , FinishTime DATETIME
    , HoursWorked DECIMAL(4, 2)
    , ShiftType VARCHAR(50)

);

INSERT INTO @Table VALUES (100,'2019-11-26','1900-01-01T02:00:00', '1900-01-01T04:00:00',2,'Normal')
INSERT INTO @Table VALUES (100,'2019-11-26','1900-01-01T05:00:00', '1900-01-01T09:00:00',4,'Tagged')
INSERT INTO @Table VALUES (100,'2019-11-26','1900-01-01T10:00:00', '1900-01-01T15:00:00',5,'Tagged')

结果集

+----------+------------+---------------------+---------------------+------------------------------+-----------+---------------+
| PersonID | WorkDate   | StartTime           | FinishTime          | HoursWorked (pre calculated) | ShiftType | EligibleHours |
+----------+------------+---------------------+---------------------+------------------------------+-----------+---------------+
| 100      | 2019-11-26 | 1900-01-01T05:00:00 | 1900-01-01T09:00:00 | 4                            | Tagged    | 4             |
+----------+------------+---------------------+---------------------+------------------------------+-----------+---------------+
| 100      | 2019-11-26 | 1900-01-01T10:00:00 | 1900-01-01T15:00:00 | 5                            | Tagged    | 2             |
+----------+------------+---------------------+---------------------+------------------------------+-----------+---------------+

Answer 1

以下是我对要求的理解：

收集每位用户每天前 8 小时完成的工作
如果班次在 8 小时之前开始并在 8 小时之后结束，则应标记用户到达 8 小时之前发生的小时数
过滤掉所有未标记的班次
过滤掉所有不符合条件的班次

为了解决我使用了两个窗口函数：

sum(TotalHours) over (...) 以确定当前班次和之前所有班次的工作小时数的累计总和
(8 - lag(CumulativeWork, 1, 0)) over (...) 以确定进入当前班次还剩多少资格。

代码如下：

select 
  PersonID,
  WorkDate,
  StartTime,
  FinishTime,
  HoursWorked,
  ShiftType,
  case 
    when RemainingWork <= HoursWorked then RemainingWork
    when RemainingWork > HoursWorked then HoursWorked 
    else 0 end as EligibleWork
from 
(
  select 
  -- Calculate how much eligible work can happen in a given shift by 
  -- subtracting the amount of work done in previous shifts from 8
  8 - lag (CumulativeWork, 1, 0) over (Partition by PersonID, WorkDate order by StartTime) as RemainingWork
  , *
  from (
    select 
    -- Create a cumulative sum of the hours worked
    sum(HoursWorked) over (Partition by PersonID, WorkDate order by StartTime) as CumulativeWork
    , *
    from ShiftTable
  ) a
) b
where shiftType = 'Tagged' and remainingWork > 0

和fiddle：http://sqlfiddle.com/#!18/7a8dd/12

SQL 查找前 8 小时内标记的总时数

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