Javascript 根据经度、纬度计算分数
Javascript Calculate Score From Longitude, Latitude
谁能帮我看看根据地理位置计算分数的方法?
将不胜感激
我正在根据纬度、经度计算分数,但没有得到预期的结果。
请看下面我的代码。我不知道我做的对还是错
这是代码片段。请 运行 代码并检查输出
const suggestions = `{
suggestions: [
{
name: "London, ON, Canada",
latitude: 42.98339,
longitude: -81.23304
},
{
name: "Londontowne, MD, USA",
latitude: 38.93345,
longitude: -76.54941
},
{
name: "London, OH, USA",
latitude: 39.88645,
longitude: -83.44825
},
{
name: "Londonderry, NH, USA",
latitude: 42.86509,
longitude: -71.37395
},
{
name: "New London, CT, USA",
latitude: 41.35565,
longitude: -72.09952
},
{
name: "New London, WI, USA",
latitude: 44.39276,
longitude: -88.73983
},
{
name: "London, KY, USA",
latitude: 37.12898,
longitude: -84.08326
}
]
}`;
console.log(calculateScore(suggestions, 43.70011, -79.4163))
function calculateScore(suggestions, latitude, longitude) {
const suggestionsResult = suggestions;
for (let i = 0; i < suggestionsResult.length; i += 1) {
let score = 0;
const lat = Math.abs(suggestionsResult[i].latitude - latitude);
const long = Math.abs(suggestionsResult[i].longitude - longitude);
score = 10 - (lat + long) / 2;
score = score > 0 ? Math.round(score) / 10 : 0;
suggestionsResult[i].score = score;
}
return suggestionsResult;
}
预期输出:
suggestions: [{
name: "London, ON, Canada",
latitude: 42.98339,
longitude: -81.23304,
score: 0.9
},
{
name: "Londontowne, MD, USA",
latitude: 38.93345,
longitude: -76.54941,
score: 0.5
},
{
name: "London, OH, USA",
latitude: 39.88645,
longitude: -83.44825,
score: 0.5
},
{
name: "Londonderry, NH, USA",
latitude: 42.86509,
longitude: -71.37395,
score: 0.5
},
{
name: "New London, CT, USA",
latitude: 41.35565,
longitude: -72.09952,
score: 0.5
},
{
name: "New London, WI, USA",
latitude: 44.39276,
longitude: -88.73983,
score: 0.5
},
{
name: "London, KY, USA",
latitude: 37.12898,
longitude: -84.08326,
score: 0.4
}
]
}```
Please help me to check the above code. I am writing correctly.
我认为您向计算方法传递的是字符串而不是对象。
某些位置的分数与您要求的值不太匹配,它们显示的分数是 0.6 而不是 0.5,但我相信逻辑是正确的。
例如,马里兰州伦敦镇与原点的距离为 3.82°(平均偏移 lat/long),因此得分将为 round(10 - 3.82) = 6 / 10 = 0.6。
我已经添加了另一种计算分数的方法,(scoreII) 只是为了好玩,它会将与原点的距离计算为 0km 的 1.00 到 1000km 或更远的 0.00 的值。 (我使用了这个优秀答案中的距离公式:calculate-distance-between-two-latitude-longitude-points-haversine-formula)
const suggestions = [ { name: "London, ON, Canada", latitude: 42.98339, longitude: -81.23304 }, { name: "Londontowne, MD, USA", latitude: 38.93345, longitude: -76.54941 }, { name: "London, OH, USA", latitude: 39.88645, longitude: -83.44825 }, { name: "Londonderry, NH, USA", latitude: 42.86509, longitude: -71.37395 }, { name: "New London, CT, USA", latitude: 41.35565, longitude: -72.09952 }, { name: "New London, WI, USA", latitude: 44.39276, longitude: -88.73983 }, { name: "London, KY, USA", latitude: 37.12898, longitude: -84.08326 } ];
console.log(calculateScore(suggestions, 43.70011, -79.4163))
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
function calculateLocationScoreII(location, latitude, longitude) {
const distanceKm = getDistanceFromLatLonInKm(location.latitude, location.longitude, latitude, longitude);
let score = 1000 - distanceKm;
score = score > 0 ? Math.round(score/10) / 100 : 0;
return score;
}
function calculateLocationScore(location, latitude, longitude) {
const lat = Math.abs(location.latitude - latitude);
const long = Math.abs(location.longitude - longitude);
let score = 10 - (lat + long) / 2;
score = score > 0 ? Math.round(score) / 10 : 0;
return score;
}
function calculateScore(suggestions, latitude, longitude) {
// Clone the suggestions.
const suggestionsResult = suggestions.map(s => { return {...s}});
return suggestionsResult.map(suggestion => {
suggestion.score = calculateLocationScore(suggestion, latitude, longitude);
suggestion.scoreII = calculateLocationScoreII(suggestion, latitude, longitude);
return suggestion;
});
}
谁能帮我看看根据地理位置计算分数的方法?
将不胜感激
我正在根据纬度、经度计算分数,但没有得到预期的结果。
请看下面我的代码。我不知道我做的对还是错
这是代码片段。请 运行 代码并检查输出
const suggestions = `{
suggestions: [
{
name: "London, ON, Canada",
latitude: 42.98339,
longitude: -81.23304
},
{
name: "Londontowne, MD, USA",
latitude: 38.93345,
longitude: -76.54941
},
{
name: "London, OH, USA",
latitude: 39.88645,
longitude: -83.44825
},
{
name: "Londonderry, NH, USA",
latitude: 42.86509,
longitude: -71.37395
},
{
name: "New London, CT, USA",
latitude: 41.35565,
longitude: -72.09952
},
{
name: "New London, WI, USA",
latitude: 44.39276,
longitude: -88.73983
},
{
name: "London, KY, USA",
latitude: 37.12898,
longitude: -84.08326
}
]
}`;
console.log(calculateScore(suggestions, 43.70011, -79.4163))
function calculateScore(suggestions, latitude, longitude) {
const suggestionsResult = suggestions;
for (let i = 0; i < suggestionsResult.length; i += 1) {
let score = 0;
const lat = Math.abs(suggestionsResult[i].latitude - latitude);
const long = Math.abs(suggestionsResult[i].longitude - longitude);
score = 10 - (lat + long) / 2;
score = score > 0 ? Math.round(score) / 10 : 0;
suggestionsResult[i].score = score;
}
return suggestionsResult;
}
预期输出:
suggestions: [{
name: "London, ON, Canada",
latitude: 42.98339,
longitude: -81.23304,
score: 0.9
},
{
name: "Londontowne, MD, USA",
latitude: 38.93345,
longitude: -76.54941,
score: 0.5
},
{
name: "London, OH, USA",
latitude: 39.88645,
longitude: -83.44825,
score: 0.5
},
{
name: "Londonderry, NH, USA",
latitude: 42.86509,
longitude: -71.37395,
score: 0.5
},
{
name: "New London, CT, USA",
latitude: 41.35565,
longitude: -72.09952,
score: 0.5
},
{
name: "New London, WI, USA",
latitude: 44.39276,
longitude: -88.73983,
score: 0.5
},
{
name: "London, KY, USA",
latitude: 37.12898,
longitude: -84.08326,
score: 0.4
}
]
}```
Please help me to check the above code. I am writing correctly.
我认为您向计算方法传递的是字符串而不是对象。
某些位置的分数与您要求的值不太匹配,它们显示的分数是 0.6 而不是 0.5,但我相信逻辑是正确的。
例如,马里兰州伦敦镇与原点的距离为 3.82°(平均偏移 lat/long),因此得分将为 round(10 - 3.82) = 6 / 10 = 0.6。
我已经添加了另一种计算分数的方法,(scoreII) 只是为了好玩,它会将与原点的距离计算为 0km 的 1.00 到 1000km 或更远的 0.00 的值。 (我使用了这个优秀答案中的距离公式:calculate-distance-between-two-latitude-longitude-points-haversine-formula)
const suggestions = [ { name: "London, ON, Canada", latitude: 42.98339, longitude: -81.23304 }, { name: "Londontowne, MD, USA", latitude: 38.93345, longitude: -76.54941 }, { name: "London, OH, USA", latitude: 39.88645, longitude: -83.44825 }, { name: "Londonderry, NH, USA", latitude: 42.86509, longitude: -71.37395 }, { name: "New London, CT, USA", latitude: 41.35565, longitude: -72.09952 }, { name: "New London, WI, USA", latitude: 44.39276, longitude: -88.73983 }, { name: "London, KY, USA", latitude: 37.12898, longitude: -84.08326 } ];
console.log(calculateScore(suggestions, 43.70011, -79.4163))
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
function calculateLocationScoreII(location, latitude, longitude) {
const distanceKm = getDistanceFromLatLonInKm(location.latitude, location.longitude, latitude, longitude);
let score = 1000 - distanceKm;
score = score > 0 ? Math.round(score/10) / 100 : 0;
return score;
}
function calculateLocationScore(location, latitude, longitude) {
const lat = Math.abs(location.latitude - latitude);
const long = Math.abs(location.longitude - longitude);
let score = 10 - (lat + long) / 2;
score = score > 0 ? Math.round(score) / 10 : 0;
return score;
}
function calculateScore(suggestions, latitude, longitude) {
// Clone the suggestions.
const suggestionsResult = suggestions.map(s => { return {...s}});
return suggestionsResult.map(suggestion => {
suggestion.score = calculateLocationScore(suggestion, latitude, longitude);
suggestion.scoreII = calculateLocationScoreII(suggestion, latitude, longitude);
return suggestion;
});
}