JPA ERROR: relation does not exist
JPA ERROR: relation does not exist
我不知道自己做错了什么。我正在按照网络上的一些教程学习 JPA 映射到关系数据库，但找不到一个简单的教程。当我 运行 我的项目时，它给我一个错误。我想这是在坚持em.persist();。如果我评论该行，一切看起来都很好，没有错误，但显然没有数据写入 table。这是我的代码：
persistence.xml（已生成，未修改）
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="RESTappPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>restapp.entities.ContactList</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:postgresql://localhost:5432/postgres"/>
<property name="javax.persistence.jdbc.user" value="postgres"/>
<property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/>
<property name="javax.persistence.jdbc.password" value="postgres"/>
</properties>
</persistence-unit>
</persistence>
实体 Class（已生成，未修改） - 我是否需要在此处添加一些额外的 'relation' 方法？
package restapp.entities;
imports [...]
@Entity
@Table(name = "ContactList")
@NamedQueries({
@NamedQuery(name = "ContactList.findAll", query = "SELECT c FROM ContactList c"),
@NamedQuery(name = "ContactList.findByFirstname", query = "SELECT c FROM ContactList c WHERE c.firstname = :firstname"),
@NamedQuery(name = "ContactList.findByLastname", query = "SELECT c FROM ContactList c WHERE c.lastname = :lastname"),
@NamedQuery(name = "ContactList.findByMobile", query = "SELECT c FROM ContactList c WHERE c.mobile = :mobile"),
@NamedQuery(name = "ContactList.findByEmail", query = "SELECT c FROM ContactList c WHERE c.email = :email")})
public class ContactList implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Basic(optional = false)
@Column(name = "firstname")
private String firstname;
@Column(name = "lastname")
private String lastname;
@Basic(optional = false)
@Column(name = "mobile")
private String mobile;
@Column(name = "email")
private String email;
// constructors
public ContactList() {
}
public ContactList(String firstname) {
this.firstname = firstname;
}
public ContactList(String firstname, String mobile) {
this.firstname = firstname;
this.mobile = mobile;
}
public ContactList(String firstname, String lastname, String mobile, String email) {
this.firstname = firstname;
this.lastname = lastname;
this.mobile = mobile;
this.email = email;
}
// getter's and setter's
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
public String getLastname() {
return lastname;
}
public void setLastname(String lastname) {
this.lastname = lastname;
}
public String getMobile() {
return mobile;
}
public void setMobile(String mobile) {
this.mobile = mobile;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
// Is something like this what it needs?
// @OneToOne(cascade=CascadeType.PERSIST)
// private Address address;
// @OneToMany(cascade=ALL, mappedBy="customer")
// public Collection<Order> getOrders() {
// return orders;
// }
@Override
public String toString() {
return "\n\n\n\n[firstname: " + firstname + "]\n"
+ "[lastname: " + lastname + "]\n"
+ "[mobile: " + mobile + "]\n"
+ "[email: " + email + "]\n\n\n\n";
}
}
Java 应用程序 Class
package restapp;
imports [...]
public class RESTapp {
private static EntityManagerFactory emf;
private static EntityManager em;
public static void main(String[] args) {
// Create EntityManagerFactory for persistent unit named "pu1" to be used in this test
emf = Persistence.createEntityManagerFactory("RESTappPU");
// Persist the customer
// em.persist(list0);
// Persist all entities
createTransactionalEntityManager();
System.out.println("Inserting Customer and Orders... " + insert());
closeTransactionalEntityManager();
}
private static String insert() {
// Create new contact
ContactList list0 = new ContactList();
list0.setFirstname("John");
list0.setLastname("Doe");
list0.setMobile("+351 91 546 33 21");
list0.setEmail("jdoe@fakemail.com");
// Create another contact
ContactList list1 = new ContactList("Jane", "Something", "+351 96 924 14 29", "jsomething@fakemail.com");
list0.toString();
// em.persist(list0);
em.persist(list0);
return "OK";
}
private static void createTransactionalEntityManager() {
// Create a new EntityManager
em = emf.createEntityManager();
// Begin transaction
em.getTransaction().begin();
}
private static void closeTransactionalEntityManager() {
// Commit the transaction
em.getTransaction().commit();
// Close this EntityManager
em.close();
}
}
当我 运行 我的项目时：
run:
[EL Info]: 2015-06-03 18:30:17.315--ServerSession(1798636297)--EclipseLink, version: Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd
[EL Info]: connection: 2015-06-03 18:30:17.689--ServerSession(1798636297)--file:/home/rsousa/NetBeansProjects/RESTapp/build/classes/_RESTappPU login successful
Inserting Customer and Orders... OK
[EL Warning]: 2015-06-03 18:30:17.794--UnitOfWork(683523720)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
Exception in thread "main" javax.persistence.RollbackException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
[mobile: +351 91 546 33 21]
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
[email: jdoe@fakemail.com]
)
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
[mobile: +351 91 546 33 21]
[email: jdoe@fakemail.com]
)
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:157)
at restapp.RESTapp.closeTransactionalEntityManager(RESTapp.java:66)
at restapp.RESTapp.main(RESTapp.java:32)
Caused by: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
[mobile: +351 91 546 33 21]
[email: jdoe@fakemail.com]
)
at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:340)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.processExceptionForCommError(DatabaseAccessor.java:1611)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:898)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeNoSelect(DatabaseAccessor.java:962)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:631)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:558)
at org.eclipse.persistence.internal.sessions.AbstractSession.basicExecuteCall(AbstractSession.java:2002)
at org.eclipse.persistence.sessions.server.ClientSession.executeCall(ClientSession.java:298)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:242)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:228)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.insertObject(DatasourceCallQueryMechanism.java:377)
at org.eclipse.persistence.internal.queries.StatementQueryMechanism.insertObject(StatementQueryMechanism.java:165)
at org.eclipse.persistence.internal.queries.StatementQueryMechanism.insertObject(StatementQueryMechanism.java:180)
at org.eclipse.persistence.internal.queries.DatabaseQueryMechanism.insertObjectForWrite(DatabaseQueryMechanism.java:489)
at org.eclipse.persistence.queries.InsertObjectQuery.executeCommit(InsertObjectQuery.java:80)
at org.eclipse.persistence.queries.InsertObjectQuery.executeCommitWithChangeSet(InsertObjectQuery.java:90)
at org.eclipse.persistence.internal.queries.DatabaseQueryMechanism.executeWriteWithChangeSet(DatabaseQueryMechanism.java:301)
at org.eclipse.persistence.queries.WriteObjectQuery.executeDatabaseQuery(WriteObjectQuery.java:58)
at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:899)
at org.eclipse.persistence.queries.DatabaseQuery.executeInUnitOfWork(DatabaseQuery.java:798)
at org.eclipse.persistence.queries.ObjectLevelModifyQuery.executeInUnitOfWorkObjectLevelModifyQuery(ObjectLevelModifyQuery.java:108)
at org.eclipse.persistence.queries.ObjectLevelModifyQuery.executeInUnitOfWork(ObjectLevelModifyQuery.java:85)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2896)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1804)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1786)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1737)
at org.eclipse.persistence.internal.sessions.CommitManager.commitNewObjectsForClassWithChangeSet(CommitManager.java:226)
at org.eclipse.persistence.internal.sessions.CommitManager.commitAllObjectsWithChangeSet(CommitManager.java:125)
at org.eclipse.persistence.internal.sessions.AbstractSession.writeAllObjectsWithChangeSet(AbstractSession.java:4207)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabase(UnitOfWorkImpl.java:1441)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabaseWithChangeSet(UnitOfWorkImpl.java:1531)
at org.eclipse.persistence.internal.sessions.RepeatableWriteUnitOfWork.commitRootUnitOfWork(RepeatableWriteUnitOfWork.java:277)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitAndResume(UnitOfWorkImpl.java:1169)
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:132)
... 2 more
Caused by: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2157)
at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:1886)
at org.postgresql.core.v3.QueryExecutorImpl.execute(QueryExecutorImpl.java:255)
at org.postgresql.jdbc2.AbstractJdbc2Statement.execute(AbstractJdbc2Statement.java:555)
at org.postgresql.jdbc2.AbstractJdbc2Statement.executeWithFlags(AbstractJdbc2Statement.java:417)
at org.postgresql.jdbc2.AbstractJdbc2Statement.executeUpdate(AbstractJdbc2Statement.java:363)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:890)
... 33 more
Java Result: 1
BUILD SUCCESSFUL (total time: 3 seconds)
IDE:NetBeans | 数据库： PostGreSQL | 持久性： EclipseLink JPA
Postgresql 将 table 和非双引号的列名转换为小写。
变化
@Table(name = "ContactList")
至
@Table(name = "contactlist")
您可以在 application.properties 中使用此配置：
spring.jpa.hibernate.naming.implicit-strategy=org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyJpaImpl
spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl
我遇到了类似的问题，但就我而言，在查询中我必须在 table 名称前加上架构名称作为前缀，因为我的数据库有多个架构并且我使用的是本机查询。
在我的例子中，问题不是精确的模式——可以在 class 的注释中提供：
@Table(name="...", schema="...")
我遇到了类似的问题，但使用了@Query 注释。
我通过在 wildfly 服务器数据源中连接 URL 的末尾指定 [?currentSchema=public] 解决了这个问题：
jdbc:postgresql://myhost:5432/mydatabase?currentSchema=public
这会在数据库用户登录时设置默认架构，并使 table 被发现。
我不知道自己做错了什么。我正在按照网络上的一些教程学习 JPA 映射到关系数据库，但找不到一个简单的教程。当我 运行 我的项目时，它给我一个错误。我想这是在坚持em.persist();。如果我评论该行，一切看起来都很好，没有错误，但显然没有数据写入 table。这是我的代码：
persistence.xml（已生成，未修改）
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="RESTappPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>restapp.entities.ContactList</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:postgresql://localhost:5432/postgres"/>
<property name="javax.persistence.jdbc.user" value="postgres"/>
<property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/>
<property name="javax.persistence.jdbc.password" value="postgres"/>
</properties>
</persistence-unit>
</persistence>
实体 Class（已生成，未修改） - 我是否需要在此处添加一些额外的 'relation' 方法？
package restapp.entities;
imports [...]
@Entity
@Table(name = "ContactList")
@NamedQueries({
@NamedQuery(name = "ContactList.findAll", query = "SELECT c FROM ContactList c"),
@NamedQuery(name = "ContactList.findByFirstname", query = "SELECT c FROM ContactList c WHERE c.firstname = :firstname"),
@NamedQuery(name = "ContactList.findByLastname", query = "SELECT c FROM ContactList c WHERE c.lastname = :lastname"),
@NamedQuery(name = "ContactList.findByMobile", query = "SELECT c FROM ContactList c WHERE c.mobile = :mobile"),
@NamedQuery(name = "ContactList.findByEmail", query = "SELECT c FROM ContactList c WHERE c.email = :email")})
public class ContactList implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Basic(optional = false)
@Column(name = "firstname")
private String firstname;
@Column(name = "lastname")
private String lastname;
@Basic(optional = false)
@Column(name = "mobile")
private String mobile;
@Column(name = "email")
private String email;
// constructors
public ContactList() {
}
public ContactList(String firstname) {
this.firstname = firstname;
}
public ContactList(String firstname, String mobile) {
this.firstname = firstname;
this.mobile = mobile;
}
public ContactList(String firstname, String lastname, String mobile, String email) {
this.firstname = firstname;
this.lastname = lastname;
this.mobile = mobile;
this.email = email;
}
// getter's and setter's
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
public String getLastname() {
return lastname;
}
public void setLastname(String lastname) {
this.lastname = lastname;
}
public String getMobile() {
return mobile;
}
public void setMobile(String mobile) {
this.mobile = mobile;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
// Is something like this what it needs?
// @OneToOne(cascade=CascadeType.PERSIST)
// private Address address;
// @OneToMany(cascade=ALL, mappedBy="customer")
// public Collection<Order> getOrders() {
// return orders;
// }
@Override
public String toString() {
return "\n\n\n\n[firstname: " + firstname + "]\n"
+ "[lastname: " + lastname + "]\n"
+ "[mobile: " + mobile + "]\n"
+ "[email: " + email + "]\n\n\n\n";
}
}
Java 应用程序 Class
package restapp;
imports [...]
public class RESTapp {
private static EntityManagerFactory emf;
private static EntityManager em;
public static void main(String[] args) {
// Create EntityManagerFactory for persistent unit named "pu1" to be used in this test
emf = Persistence.createEntityManagerFactory("RESTappPU");
// Persist the customer
// em.persist(list0);
// Persist all entities
createTransactionalEntityManager();
System.out.println("Inserting Customer and Orders... " + insert());
closeTransactionalEntityManager();
}
private static String insert() {
// Create new contact
ContactList list0 = new ContactList();
list0.setFirstname("John");
list0.setLastname("Doe");
list0.setMobile("+351 91 546 33 21");
list0.setEmail("jdoe@fakemail.com");
// Create another contact
ContactList list1 = new ContactList("Jane", "Something", "+351 96 924 14 29", "jsomething@fakemail.com");
list0.toString();
// em.persist(list0);
em.persist(list0);
return "OK";
}
private static void createTransactionalEntityManager() {
// Create a new EntityManager
em = emf.createEntityManager();
// Begin transaction
em.getTransaction().begin();
}
private static void closeTransactionalEntityManager() {
// Commit the transaction
em.getTransaction().commit();
// Close this EntityManager
em.close();
}
}
当我 运行 我的项目时：
run:
[EL Info]: 2015-06-03 18:30:17.315--ServerSession(1798636297)--EclipseLink, version: Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd
[EL Info]: connection: 2015-06-03 18:30:17.689--ServerSession(1798636297)--file:/home/rsousa/NetBeansProjects/RESTapp/build/classes/_RESTappPU login successful
Inserting Customer and Orders... OK
[EL Warning]: 2015-06-03 18:30:17.794--UnitOfWork(683523720)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
Exception in thread "main" javax.persistence.RollbackException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
[mobile: +351 91 546 33 21]
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
[email: jdoe@fakemail.com]
)
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
[mobile: +351 91 546 33 21]
[email: jdoe@fakemail.com]
)
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:157)
at restapp.RESTapp.closeTransactionalEntityManager(RESTapp.java:66)
at restapp.RESTapp.main(RESTapp.java:32)
Caused by: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
Error Code: 0
Call: INSERT INTO ContactList (firstname, email, lastname, mobile) VALUES (?, ?, ?, ?)
bind => [4 parameters bound]
Query: InsertObjectQuery(
[firstname: John]
[lastname: Doe]
[mobile: +351 91 546 33 21]
[email: jdoe@fakemail.com]
)
at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:340)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.processExceptionForCommError(DatabaseAccessor.java:1611)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:898)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeNoSelect(DatabaseAccessor.java:962)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:631)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:558)
at org.eclipse.persistence.internal.sessions.AbstractSession.basicExecuteCall(AbstractSession.java:2002)
at org.eclipse.persistence.sessions.server.ClientSession.executeCall(ClientSession.java:298)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:242)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:228)
at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.insertObject(DatasourceCallQueryMechanism.java:377)
at org.eclipse.persistence.internal.queries.StatementQueryMechanism.insertObject(StatementQueryMechanism.java:165)
at org.eclipse.persistence.internal.queries.StatementQueryMechanism.insertObject(StatementQueryMechanism.java:180)
at org.eclipse.persistence.internal.queries.DatabaseQueryMechanism.insertObjectForWrite(DatabaseQueryMechanism.java:489)
at org.eclipse.persistence.queries.InsertObjectQuery.executeCommit(InsertObjectQuery.java:80)
at org.eclipse.persistence.queries.InsertObjectQuery.executeCommitWithChangeSet(InsertObjectQuery.java:90)
at org.eclipse.persistence.internal.queries.DatabaseQueryMechanism.executeWriteWithChangeSet(DatabaseQueryMechanism.java:301)
at org.eclipse.persistence.queries.WriteObjectQuery.executeDatabaseQuery(WriteObjectQuery.java:58)
at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:899)
at org.eclipse.persistence.queries.DatabaseQuery.executeInUnitOfWork(DatabaseQuery.java:798)
at org.eclipse.persistence.queries.ObjectLevelModifyQuery.executeInUnitOfWorkObjectLevelModifyQuery(ObjectLevelModifyQuery.java:108)
at org.eclipse.persistence.queries.ObjectLevelModifyQuery.executeInUnitOfWork(ObjectLevelModifyQuery.java:85)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2896)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1804)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1786)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1737)
at org.eclipse.persistence.internal.sessions.CommitManager.commitNewObjectsForClassWithChangeSet(CommitManager.java:226)
at org.eclipse.persistence.internal.sessions.CommitManager.commitAllObjectsWithChangeSet(CommitManager.java:125)
at org.eclipse.persistence.internal.sessions.AbstractSession.writeAllObjectsWithChangeSet(AbstractSession.java:4207)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabase(UnitOfWorkImpl.java:1441)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabaseWithChangeSet(UnitOfWorkImpl.java:1531)
at org.eclipse.persistence.internal.sessions.RepeatableWriteUnitOfWork.commitRootUnitOfWork(RepeatableWriteUnitOfWork.java:277)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitAndResume(UnitOfWorkImpl.java:1169)
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:132)
... 2 more
Caused by: org.postgresql.util.PSQLException: ERROR: relation "contactlist" does not exist
Position: 13
at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2157)
at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:1886)
at org.postgresql.core.v3.QueryExecutorImpl.execute(QueryExecutorImpl.java:255)
at org.postgresql.jdbc2.AbstractJdbc2Statement.execute(AbstractJdbc2Statement.java:555)
at org.postgresql.jdbc2.AbstractJdbc2Statement.executeWithFlags(AbstractJdbc2Statement.java:417)
at org.postgresql.jdbc2.AbstractJdbc2Statement.executeUpdate(AbstractJdbc2Statement.java:363)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:890)
... 33 more
Java Result: 1
BUILD SUCCESSFUL (total time: 3 seconds)
IDE:NetBeans | 数据库： PostGreSQL | 持久性： EclipseLink JPA
Postgresql 将 table 和非双引号的列名转换为小写。 变化
@Table(name = "ContactList")
至
@Table(name = "contactlist")
您可以在 application.properties 中使用此配置：
spring.jpa.hibernate.naming.implicit-strategy=org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyJpaImpl spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl
我遇到了类似的问题，但就我而言，在查询中我必须在 table 名称前加上架构名称作为前缀，因为我的数据库有多个架构并且我使用的是本机查询。
在我的例子中，问题不是精确的模式——可以在 class 的注释中提供：
@Table(name="...", schema="...")
我遇到了类似的问题，但使用了@Query 注释。
我通过在 wildfly 服务器数据源中连接 URL 的末尾指定 [?currentSchema=public] 解决了这个问题：
jdbc:postgresql://myhost:5432/mydatabase?currentSchema=public
这会在数据库用户登录时设置默认架构，并使 table 被发现。